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zvonat [6]
2 years ago
9

Find the GCF of the first two terms and the GCF of the last two terms of the polynomial. 5h^3+20h^2+4h+16

Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0
The GCF of the first two terms: 5h²
The GCF of the last two terms: 4

5h³ and 20h² 

Both of these terms are divisible by 5. (constant)
Both of these terms also have at least 2 h's. (variable)

4h and 16

Both of these terms are divisible by 4. 
Only one term has a variable, so that has to be left out.



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Question 4 Which is a TRUE statement about the transformation shown?
ioda

Answer:

reflection

Step-by-step explanation:

the second picture is the same distance away form the y axis as the first picture

6 0
2 years ago
In the circle below, suppose m FEH=272º and m EFG=116º. Find the following.​
adoni [48]

Answer:

m∠FEH = 44°

m∠EHG =  64°

Step-by-step explanation:

1) The given information are;

The angle of arc m∠FEH = 272°, the measured angle of ∠EFG = 116°

Given that m∠FEH = 272°, therefore, arc ∠HGF = 360 - 272 = 88°

Therefore, angle subtended by arc ∠HGF at the center = 88°

The angle subtended by arc ∠HGF at the circumference = m∠FEH

∴ m∠FEH = 88°/2 = 44° (Angle subtended at the center = 2×angle subtended at the circumference)

m∠FEH = 44°

2) Similarly, m∠HGF is subtended by arc m FEH, therefore, m∠HGF = (arc m FEH)/2 = 272°/2 = 136°

The sum of angles in a quadrilateral = 360°

Therefore;

m∠FEH + m∠HGF + m∠EFG + m∠EHG = 360° (The sum of angles in a quadrilateral EFGH)

m∠EHG = 360° - (m∠FEH + m∠HGF + m∠EFG) = 360 - (44 + 136 + 116) = 64°

m∠EHG =  64°.

5 0
3 years ago
Can someone plz help me solve this..
Vika [28.1K]

Answer:sorry I'm a 4 grader

Step-by-step explanation:

7 0
2 years ago
Please help I hate geometry
finlep [7]

transverse s at angle 135°

180° - 135° = 45°

Angle 2 is congruent to 45° because they're alternate exterior angles.

transverse t at angle 120°

180° - 120° = 60°

Angle 3 is congruent to 60° because they're alternate exterior angles.

One rule for exterior angles in triangles is that the exterior angle is equal to the sum of the two angles adjacent to the opposite angle of the exterior angle.

135° = angle 1 + 60°

angle 1 = 75°

120° = angle 1 + 45°

angle 1 = 75°

Therefore angle 1 is 75°,angle 2 is 45° and angle 3 is 60°

7 0
2 years ago
Read 2 more answers
The line represented by the equation 4y + 2x = 33.6 shares a solution point with the line represented by the table
mamaluj [8]

Answer:

The solution of this system is

(4). (6.0,5.4)

Step-by-step explanation:

First we have to find the equation of the line represented in the table; for that we have to find it's slope m and it's y-intercept b and then write it in the following form:

y=mx+b

The slope m of the line we get from first two points:

m=\frac{3.8-3.2}{(-2)-(-5)} =0.2

thus we have

y=0.2x+b

we find b by putting the point (2,4.6) into the function:

4.6=0.2(2)+b

b=4.6-0.4=4.2

Thus we have

y=0.2x+4.2

Now we have to find where this line intersects with 4y+2x=33.6; to do this we just substitute y with y=0.2x+4.2:

4(0.2x+4.2)+2x=33.6

0.8x+16.8+2x=33.6

\boxed{x=6 }

<em>We have the x-coordinate of  the intersection.</em>

We find the y-coordinate by substituting x=6 into y=0.2x+4.2:

y=0.2(6)+4.2=5.4

\boxed{y=5.4}

Thus the solution to the system is

\boxed{(x,y)=(6, 5.4)}

which is option 4.

4 0
3 years ago
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