We know that: <span>3(x-1)^2-162=0
or (x-1)</span>²= 162:3
and (x-1)²= 54
we <span>take the square root of both sides
* x-1=</span>√54= 3√6 or x=1+3√6
* x-1= -<span>√54= -3√6 or x=1-3√6
This equation has 2 solutions</span>
The equation of a circle with centre (a,b) and radius r is:
(x - a)^2 + (y - b)^2 = r^2
thus,
here centre (a,b) = (-3,6), a = -3, b = 6
and radius = diameter/2 = 20/2 =10 units
therefore, the equation is
(x + 3)^2 + (y - 6)^2 = 100
which is c.
Answer:
The answer is point C
Step-by-step explanation:
Point C is the opposite of point P
What you have to find is what numbers add to -6 and multiply to 9. these numbers would be -3 and -3 (-3+-3=-6, -3*-3=9). substitute these in for -6x as x^2-3x-3x+9=0. then factor out c and three to get x(x-3)-3(x-3)=0. x-3=0 in both cases, so x is three.
