Please help me with this question

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

4 0

Hello! I can help you! For this question, you have to subtract different numbers in order to find the missing boxes. For example, to find the amount made on 1st Lunch Thursday, subtract the total under that empty box from the amount made on 1st Lunch Tuesday. You have to do some work to find the answers, but it’s basically subtraction from the totals in order to fill in the empty boxes. With that being said, here are the answers if you solve it correctly.

2nd Lunch Tuesday: $18.80
1st Lunch Thursday: $29.10
3rd Lunch Thursday: $31.25
Total on all Tuesday’s: $66.15
Total on 2nd Week Lunch: $45.15
Total Overall: $152.85

Note: Be sure to put these in the right column. For the all Tuesday’s amount, it goes on the top right box. The 2nd Week Lunch amount goes on the last box of the 2nd Lunch column. The overall total goes on the bottom right box. Just so you know.

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What is the solution of x=2+ square root x-2?

alex41 [277]

So I'm going to assume that this question is asking for non extraneous solutions, or solutions that are found in the equation and are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

$x-2=\sqrt{x-2}$

Next, square both sides:

$(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2$

Next, subtract x and add 2 to both sides of the equation:

$x^2-5x+6=0$

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

$x^2-2x-3x+6=0$