A town's public works department is concerned that a certain intersection is dangerous for cars and
1 answer:
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Assuming the equation is:
When fractions involve numeric denominators, the fractions can be removed by multiplying (both sides) by the LCM of the denominators.
Here the denominators are 2 and 10, hence the LCM is 10.
Multiply by 10 on both sides, not forgetting to distribute when multiplying on the right side:
simplify, remember that there are always implied parentheses around numerators and denominators:
Now, distribute, i.e. remove parentheses and distribute:
5x-10x+25=30x+90-10x+140
Simplify
-5x+25=20x+230
transpose terms
25-230=20x+5x
solve
x=-205/25=-41/5
In this particular case, we can also take advantage of the term
(10x-25)/10=5(2x-5)/10=(2x-5)/2 which greatly simplifies the solution process, because the LCM will then be 2 instead of 10.
If we do that, the solution will be:
Multiply by 2 on both sides, not forgetting to distribute when multiplying on the right side:
simplify, remember that there are always implied parentheses around numerators and denominators:
Now, distribute, i.e. remove parentheses and distribute:
Simplify
-x+5=4x+46
solve
5-46=4x+x
-41=5x
x=-41/5
with the same results.
<h2>Greetings</h2>
<h2>Hope this helps!</h2>
Answer:
Yes, they are.
Step-by-step explanation:
<h3>1st rate)</h3>Lets simplify both rates to the rate typer per minute.
(m is minutes)
3m = 96
Divide both sides by 3:
m = 32
So the rate is 32 words per minute.
<h3>2nd rate</h3>5m = 160
Divide both sides by 5:
m = 32
<h3>So because the rates per minute are the same, they are equivalent.</h3><h2>Hope this helps!</h2>
Answer:
1) n = 39916800
2) n = 1663200
3) n = 330
Step-by-step explanation:
1) If the blue balls are distinguishable as are the red balls
Then you can arrange these balls in the following ways, we must use a permutation
In totally we have 11 balls, then
n = 11P11
2) If Blue balls are distinguishable, but the red balls are identical
In this case, we need to do a correction due to the red balls are identical and we cannot identify the difference when we interchange two red balls
3) If the balls of each color are indistinguishable
We proceed equal to the before case but we include a correction due to blue balls also