Edited 2018-03-09 07:49
Given unit circle, so radius=1.
We calculate lengths of vertical segments, with the help of Pythagoras Theorem, based on a right triangle radiating from circle centre O, and hypotenuse from O to a point on the circumference.
AO=1 (given unit circle)
BB'=sqrt(1^2-0.25^2)=0.968246
CC'=sqrt(1^2-0.5^2)=0.866025
DD'=sqrt(1^2-0.75^2)=0.661438
EE'=0
Now we proceed to calculate the segments approximating the arc. Again, we use a right triangle in which the hypotenuse is the segment joining two points on the circumference. The height is the difference between the two vertical segments, and the base is 0.25 for all four segments.
AB=sqrt((AO-BB)^2+0.25^2)=0.252009BC=sqrt((BB-CC)^2+0.25^2)=0.270091CD=sqrt((CC-DD)^2+0.25^2)=0.323042DE=sqrt((DD-0)^2+0.25^2)=0.7071068
giving a total estimation of the arc length
approximation of arc=AB+BC+CD+DE=1.55225
if you isolate y in the top equation to get y=5x+6 then you can substiture y for 5x+6 in the bottom equation because thats what y equals
as of now you have -3x+6(5x+6)=-12 but if you use the distrubite property you would get -3x+30x+36=-12
then if you subtract 36 from both sides you would get -3x+30x=-48 then combine like terms to get 27x=-48 then divide both sides by 27 to get
or x≈1.8
Answer:
8 feet per second.
Step-by-step explanation:
We have been given that a car is driving away from a crosswalk. The formula
expresses the car's distance from the crosswalk in feet, d, in terms of the number of seconds, t, since the car started moving.
We will use average change formula to solve our given problem.





Therefore, the the car's average speed over the given interval of time would be 8 feet per second.
Answer:
6h² + 3h + 5
Step-by-step explanation:
7h² + 2h + 5 - h² + h
= 7h² - h² + 2h + h + 5
= 6h² + 3h + 5