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3 years ago

A countertop is 16 feet long and 3 feet wide . what is the area of the countertop in square meters?

Mathematics

2 answers:

Ivenika [448]3 years ago

8 0

You just do 16 times 3 to find teh area
you get 48 square meters

Rus_ich [418]3 years ago

4 0

Answer: It asked for feet not meters. Anyways, that answer of 48 meters is wrong. It should be 48 feet converted to meter which is 54.652 meters.

Step-by-step explanation:

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The area of 14 cm wide rectangle is 252 CM what is the length

Olin [163]

Answer: 21cm

Step-by-step explanation:

To find the area of a rectangle you just multiply the length by the width. In this case we have 12(width) x ?(length) = 252. To solve we would just divide the area by the known measurement to find the missing one, so 252/12 =21cm

5 0

3 years ago

Write the equation for this line in slope-intercept form

dimulka [17.4K]

Answer:

y=x-1

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Who can help me d e f thanks

12345 [234]

$y = (2ax^2 + c)^2 (bx^2 - cx)^{-1}$

Product rule:

$y' = \bigg((2ax^2+c)^2\bigg)' (bx^2-cx)^{-1} + (2ax^2+c)^2 \bigg((bx^2-cx)^{-1}\bigg)'$

Chain and power rules:

$y' = 2(2ax^2+c)\bigg(2ax^2+c\bigg)' (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} \bigg(bx^2-cx\bigg)'$

Power rule:

$y' = 2(2ax^2+c)(4ax) (bx^2-cx)^{-1} - (2ax^2+c)^2 (bx^2-cx)^{-2} (2bx - c)$

Now simplify.

$y' = \dfrac{8ax (2ax^2+c)}{bx^2 - cx} - \dfrac{(2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y' = \dfrac{8ax (2ax^2+c) (bx^2 - cx) - (2ax^2+c)^2 (2bx-c)}{(bx^2-cx)^2}$

$y = \dfrac{3bx + ac}{\sqrt{ax}}$

Quotient rule:

$y' = \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{\left(\sqrt{ax}\right)^2}$

$y'= \dfrac{\bigg(3bx+ac\bigg)' \sqrt{ax} - (3bx+ac) \bigg(\sqrt{ax}\bigg)'}{ax}$

Power rule:

$y' = \dfrac{3b \sqrt{ax} - (3bx+ac) \left(-\frac12 \sqrt a \, x^{-1/2}\right)}{ax}$

Now simplify.

$y' = \dfrac{3b \sqrt a \, x^{1/2} + \frac{\sqrt a}2 (3bx+ac) x^{-1/2}}{ax}$

$y' = \dfrac{6bx + 3bx+ac}{2\sqrt a\, x^{3/2}}$

$y' = \dfrac{9bx+ac}{2\sqrt a\, x^{3/2}}$

$y = \sin^2(ax+b)$

Chain rule:

$y' = 2 \sin(ax+b) \bigg(\sin(ax+b)\bigg)'$

$y' = 2 \sin(ax+b) \cos(ax+b) \bigg(ax+b\bigg)'$

$y' = 2a \sin(ax+b) \cos(ax+b)$

We can further simplify this to

$y' = a \sin(2(ax+b))$

using the double angle identity for sine.

7 0

1 year ago

Think of positive integer/ multiply the number by 2/ add 6/ divide 2 /subtract the original number in step 1/ the magic number i

Tresset [83]

Positive integer: 2
2*2 = 4
4 + 6 = 10
10/2 = 5
5-2 = 3

8 0

3 years ago

What is the term to term rule for this sequence 64 32 16 8 4

nikklg [1K]

Answer:

Divide by 2 each time.

Step-by-step explanation:

The rule is dividing by 2 each time.

64/2=32

32/2=16

16/2=8

8/2=4

Hope this helps you!! Have an amazing day, and happy thanksgiving ^^

4 0

3 years ago