Answer:
169
Step-by-step explanation:
5² + 12²
25 + 144
169
I believe it can be written as 1
or
Hello!
hint: we can rewrite your function as below:
<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π =
=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)
</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:
<span>"4P=π"
Hope this Helps! Have A Wonderful Day! :)</span>
Answer:
x = 4
, y = 2
Step-by-step explanation by elimination:
Solve the following system:
{2 x + 3 y = 14 | (equation 1)
x + 5 y = 14 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x + 3 y = 14 | (equation 1)
0 x+(7 y)/2 = 7 | (equation 2)
Multiply equation 2 by 2/7:
{2 x + 3 y = 14 | (equation 1)
0 x+y = 2 | (equation 2)
Subtract 3 × (equation 2) from equation 1:
{2 x+0 y = 8 | (equation 1)
0 x+y = 2 | (equation 2)
Divide equation 1 by 2:
{x+0 y = 4 | (equation 1)
0 x+y = 2 | (equation 2)
Collect results:
Answer: {x = 4
, y = 2
