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3 years ago

Why do you think that some asteroids tumble end over end through space while other asteroids rotate around their axis?

1 answer:

6 0

Asteroids do this because of Newton's Third Law. When a asteroid hits something, it will keep on moving (spinning) until it hits something else.

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Does natural selection produce a change in individuals or populations?

butalik [34]

Explanation:

Natural selection is the process through which populations of living organisms adapt and change. Individuals in a population are naturally variable, meaning that they are all different in some ways. This variation means that some individuals have traits better suited to the environment than others

6 0

3 years ago

A spring with a spring constant of 4 N/m is stretched by Sarah's dog until extended by 2 m. How much elastic potential energy is

azamat

Hi there!

Recall the equation for spring potential energy:

$PE = \frac{1}{2}kx^2$

k = Spring constant (N/m)

x = extension of spring from equilibrium (m)

PE = Potential Energy (J)

Plug in the given values:

$PE = \frac{1}{2}(4)(2^2) = \boxed{8 J}$

8 0

3 years ago

Gravity will have a greater effect on an object with

prohojiy [21]

The correct option is B. More mass

Hope this helps you

Brainliest would be appreciated

-AaronWiseIsBae

7 0

3 years ago

Read 2 more answers

Is telekinesis real??? I really wanna start learning it!

Lesechka [4]

Answer:

if you only have to control your chakra and know how to get all your vibes to pass it to objects and it takes time to practice

4 0

3 years ago

In a maneuver, the jet comes in for a landing on solid ground with a speed of 115 m/s, and its acceleration can have a maximum m

V125BC [204]

Answer:

17.1130952381 s

Explanation:

t = Time taken

u = Initial velocity = 115 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = -6.72 m/s² (negative as it is decelerating)

From the equations of motion

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-115}{-6.72}\\\Rightarrow t=17.1130952381\ s$

The minimum time required to stop is 17.1130952381 s

$v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-115^2}{2\times -6.72}\\\Rightarrow s=984.00297619\ m$

The distance that is required for the jet to stop is 0.98400297619 km which is greater than 0.8 km. So, the jet cannot land on a small tropical island airport.

4 0

3 years ago