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3 years ago

When area increases, pressure decreases. Find two situations where this principle is applied.

Physics

1 answer:

BigorU [14]3 years ago

5 0

Answer:

Explanation:

Pressure can be defined as the force per unit area hence there is an inverse relationship between pressure exerted by a substance and the area of that substance. For instance,

(1) if a bag of sand if filled with sand and an individual steps on this bag. The feet of he individual will form no shape/displace little sand sideways in the bag. But if the same quantity of sand is poured in a bigger bag (larger area) and the same individual stands on the bag, the feet of the individual will "sink" (decreased pressure from the bag) displacing some sand sideways.

(2) The straps of a bag are made wide (and not slim) so that the bag can exert lesser pressure on the shoulders when the same quantity of load is carried by the bag than if the straps were made narrow/slim.

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What will be the ME of a machine that produces a 240 N work with a 300

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Answer:

Efficiency = 80%

Explanation:

Given the following data;

Work output = 240 N

Work Input = 300 N

To find the mechanical efficiency of a machine;

$Efficiency = \frac {Out-put \; work}{In-put \; work} * 100$

Substituting into the equation, we have;

$Efficiency = \frac {240}{300} * 100$

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4 years ago

Consider a two-dimensional projectile motion problem involving a ball starting and ending at the same height. the projectile lea

mariarad [96]

The range of the projectile is maximum at angle 45°, the range is 10.2m, the time to reach the maximum height is 0.72 s and the maximum height is 2.6 m

<h3>What is a Projectile ?</h3>

The stone, or object or anything projected in a trajectory path is known as a projectile.

In the given two-dimensional projectile motion problem involving a ball starting and ending at the same height. the projectile leaves the ground with an initial velocity of 10 m/s at some angle Ф with the horizontal,

(a) The value of the angle Ф (in degrees) which will makes the range of the projectile maximum is angle 45° because Range = u²sin2Ф ÷ g

At Ф = 45

Range = u²sin90° ÷ g

where sin 90 = 1

So, Range = u² / g which is the maximum range.

(b) The range at this angle will be

Range = 10² ÷ 9.8

Range = 100 / 9.8

Range = 10.2 m

(c) To calculate how long it takes the ball to reach maximum height, we will use the formula

t = usinФ ÷ g

t = 10 sin 45 ÷ 9.8

t = 0.72s

(d) The maximum height will be

H = u²sin²Ф ÷ 2g

H = 10²(sin45)² ÷ 2 × 9.8

H = 100 × 0.5 ÷ 19.6

H = 50 ÷ 19.6

H = 2.55 m

Therefore, the range of the projectile is maximum at angle 45°, the range is 10.2m, the time to reach the maximum height is 0.72 s and the maximum height is 2.6 m

Learn more about Projectile here: brainly.com/question/12870645

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