Area enclosed in radians =$\pi r^2$
so area enclosed in $\theta$ radians=$\theta \times \frac{\pi r^2}{2\pi}= \frac{1}2\theta r^2$
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The landscaper charges a rate of $40 per hour to plant trees.
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First we take the two points (-7,5) and (-5,9).
Compute the slope:
Then the linear relation may be in the following form
Since the point (-7,5) is on the line, then
The relation is then
.
We check that the other point are on the above line:
We have then a linear relation.
Compute the slope:
Then the linear relation may be in the following form
Since the point (-7,5) is on the line, then
The relation is then
We check that the other point are on the above line:
We have then a linear relation.