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BartSMP [9]
3 years ago
7

What is the simplified form of −x2 (2x3 + 5x2 + 6x)?

Mathematics
1 answer:
allsm [11]3 years ago
6 0
I Believe It’s 2x^5-5x^4-6x^3
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Find the ratio of the geometric sequence 11,99,891
nadya68 [22]

Answer:

Ratio is 9

Step-by-step explanation:

Common ratio can be obtained by dividing second term by first term, third term by second term etc

Therefore

99/11 = 9

891/99 = 9

The common ratio is 9

8 0
3 years ago
Which fraction is equivalent to that number? HELP NEEDED ASAP
solong [7]

Answer:

2/3

Step-by-step explanation:

Let n = the repeating, non-terminating number 0.666...

We now have n = 0.666666...

We want the number n in the form of a fraction.

Since only 1 digit repeats, the 6, use a 1 followed by 1 zero, which means the number 10. Now multiply both sides by 10 and write the original equation below it.

10n = 6.666666...

   n = 0.666666...

Subtract the bottom equation from the top equation.

9n = 6

n = 6/9

n = 2/3

6 0
3 years ago
WILL GIBE BRAINLIEST ASAP
Romashka [77]

Answer:

A and D have whole grid squares that are the same size and aren't over lapping

C has overlapping grid squares making it hard to count

B can't be used to find area because some of the grid squares are different sizes

You still could use B because four of the smaller squares seems to be equivalent to one of the larger squares

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What percent of 96.4 is 23.4
Kipish [7]

Answer:

x = 24.27385%

Step-by-step explanation:

We can say 96.4x=23.4

Divide by 96.4: (x=23.4/96.4) = 0.24273858921

x=0.24273858921 so x = 24.27385...%

7 0
1 year ago
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Temka [501]

Answer:

It diverges.

Step-by-step explanation:

We are given the inetegral:  \int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx

\int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx=\int\limits^{\infty}_2 (\ln x)^2 d(\ln x)=\\\\=\lim_{t \to \infty} \int\limits^t_2 (\ln x)^2d(\ln x)=\lim_{t \to \infty} \frac{(\ln t)^3}{3} |^t_2=\infty-\frac{(\ln 2)^3}{3} =\infty

So it is divergent.

7 0
3 years ago
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