The graph of which of the following will be parallel to the graph of 4x – 3y = –12?

1 answer:

8 0

First, we need to write the equation into the form y=mx + b which is as follows:

4x – 3y = –12
y = (4/3)x + 12

For an equation to be parallel, they should have the same slope. For this case, the slope should be 4/3. I believe the correct answer is option A. The graph of y=4/3x - 3/2 will be parallel to the graph of 4x – 3y = –12.

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Please show work for both problems

pentagon [3]

Answer:

1) x = 25 2) x = 23; m∠CBD = 80 degrees

Step-by-step explanation:

1) 5x + 15 = 6x - 10 Set both equations equal to each other

- 5x - 5x Subtract 5x from both sides

15 = x - 10

+ 10 + 10 Add 10 to both sides

25 = x

2) 2x + 14 + x + 7 = 90 Set the equations equal to 90

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- 21 - 21 Subtract 21 on both sides

3x = 69 Divide both sides by 3

x = 23

Plug 23 into the equation

2(23) + 14 = 60

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Answer:

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Step-by-step explanation:

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A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

Answer-

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

Solution-

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$