Hypotenuse of the right triangle: h=sqrt(4^2+6^2)
h=sqrt(16+36)
h=sqrt(52)
h=sqrt(4*13)
h=sqrt(4) sqrt(13)
h=2 sqrt(13)
Total Area: T.A.=2*(4*6/2)+[4+6+2 sqrt(13)] (8)
T.A.=2*(12)+[10+2 sqrt(13)](8)
T.A.=24+(10)(8)+[2 sqrt(13)](8)
T.A.=24+80+16 sqrt(13)
T.A.=104+16 sqrt(13)
Answer:
( 104+16 sqrt(13) )
Answer: an improper fraction
Step-by-step explanation: An improper fraction is a fraction that is larger than 1 7/3 is larger than one because 7, the numerator is larger than the denominator so 7/3 is an improper fraction
What you must do in this case is to find the roots of the polynomial.
We have then:
x ^ 2 + 20x + 100 = 36
Rewriting:
x ^ 2 + 20x + 64 = 0
The values of the roots are:
x1 = -4
x2 = -16
Remember that the values of the roots are what make the polinome zero
Answer:
x1 = -4
x2 = -16
Answer:
300 square units
Step-by-step explanation:
explanation-because i just know
