Answer:
![x(\sqrt[12]{x^5} )](https://tex.z-dn.net/?f=x%28%5Csqrt%5B12%5D%7Bx%5E5%7D%20%29)
Step-by-step explanation:
We need to remember 2 rules when doing these:
1. ![\sqrt[n]{x^a} =x^{\frac{a}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ea%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bn%7D%7D)
2. 
Using these 2 rules, we can simplify the product (steps shown below):
![\sqrt[3]{x^2} *\sqrt[4]{x^3} \\=x^{\frac{2}{3}}*x^{\frac{3}{4}}\\=x^{\frac{2}{3}+\frac{3}{4}}\\=x^{\frac{17}{12}}\\=x^{\frac{12}{12}+\frac{5}{12}}\\=x(x^{\frac{5}{12}})\\=x(\sqrt[12]{x^5} )](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E2%7D%20%2A%5Csqrt%5B4%5D%7Bx%5E3%7D%20%5C%5C%3Dx%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%2Ax%5E%7B%5Cfrac%7B3%7D%7B4%7D%7D%5C%5C%3Dx%5E%7B%5Cfrac%7B2%7D%7B3%7D%2B%5Cfrac%7B3%7D%7B4%7D%7D%5C%5C%3Dx%5E%7B%5Cfrac%7B17%7D%7B12%7D%7D%5C%5C%3Dx%5E%7B%5Cfrac%7B12%7D%7B12%7D%2B%5Cfrac%7B5%7D%7B12%7D%7D%5C%5C%3Dx%28x%5E%7B%5Cfrac%7B5%7D%7B12%7D%7D%29%5C%5C%3Dx%28%5Csqrt%5B12%5D%7Bx%5E5%7D%20%29)
Rearranging, we see that it is the third choice.
Answer:
give it
Step-by-step explanation:
For numbers 15-17, we need to remember that two of a triangle's angles are always acute and the third angle will allow us to classify the triangle based on its angles. now that we know this, let's look at #15. the first two angles listed are acute, and the third is an obtuse angle, therefore it is an obtuse triangle. on #16 we have three acute angles, so it is an acute triangle. #17 has two acute angles and a right angle so it is a right triangle.
on numbers 21-23, we need to know that a triangle with all congruent sides is called equilateral, a triangle with two equal sides is isosceles, and a triangle with no equal sides is called scalene. #21 shows two equal sides so it is an isosceles triangle. #22 has three equal sides so it is an equilateral triangle. #23 has no equal sides so it is scalene. hope this helped! :)
Answer: a=36; b=18
Step-by-step explanation:
1. You know that the sum of two numbers is 54, then, you have:
a+b=54
2. According to the problem, the larger number is 18 more than the sampler number, this can be expressed as following:
a=b+18
3. Then, you must substitute the second equation into the first equation and solve for b:
b+18+b=54
b=18
4. Then the value of a is:
a+18=55
a=36
