All categories

3 years ago

What is the solution to the system of equations graphed below?

Mathematics

1 answer:

Nana76 [90]3 years ago

4 0

Answer: (2, -3)

Step-by-step explanation:

Look at the point where the two graphed lines cross.

The first number in the solution is the x-value, that is how far to the left or right you count from the center O. 2 to the right +2

The second number in the solution is the y-value, that is how fat up or down you count from the center O. 3 down is -3

When you have those two values, you express them as the "coordinates" of that point. in this case (2, -3)

You might be interested in

What fractional part of the bar is blue? ill mark brainliest!

Snezhnost [94]

Answer:

3/6 or 1/2

Step-by-step explanation:

⇒ out of 6 blocks 3 are shaded so, it will be 3/6

⇒ out of 6 blocks 3 are shaded (3 is half of 6) so, it will be 1/2

3 0

3 years ago

Read 2 more answers

Help me solve please

Lisa [10]

Answer:

degree measure of arc AB = 120°

length of arc AB = 40π/3 in.

Step-by-step explanation:

arc AB has the same measure as its central angle. So, arc AB = 120°

120 is 1/3 of 360, Therefore, the length of arc AB is 1/3 of the circumference.

Therefore, the

length of arc AB = 1/3πd = 1/3π(40) =

= 40π/3 in.

5 0

3 years ago

A. 2x = 5 What would be the answer I don’t know anyone help me before the 28th

Aleksandr [31]

Answer:

2.5

Step-by-step explanation:

4 0

3 years ago

(845,230) +-834 -0.4556=

Levart [38]

(845,230) +-834 -0.4556= 844395.5444

7 0

4 years ago

Read 2 more answers

There is a photo attached tan 270 is incorrect!

wlad13 [49]

$\dfrac{1-\cos135^\circ}{\sin135^\circ}=\dfrac{1-\left(\cos^2 67.5^\circ-\sin^2 67.5^\circ\right)}{2\sin67.5^\circ\cos67.5^\circ}=\dfrac{1-\left(1-\sin^2 67.5^\circ-\sin^2 67.5^\circ\right)}{2\sin67.5^\circ\cos67.5^\circ}=\medskip\\=\dfrac{2\sin^2 67.5^\circ}{2\sin67.5^\circ\cos67.5^\circ}=\dfrac{\sin 67.5^\circ}{\cos 67.5^\circ}=\tan 67.5^\circ$

3 0

3 years ago