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Montano1993 [528]
3 years ago
10

What is the solution to the system of equations graphed below?

Mathematics
1 answer:
Nana76 [90]3 years ago
4 0

Answer:  (2, -3)

Step-by-step explanation:

Look at the point where the two graphed lines cross.  

The first number in the solution is the x-value,  that is how far to the left or right you count from the center O.  2 to the right +2

The second number in the solution is the y-value, that is how fat up or down you count from the center O.   3 down is -3

When you have those two values, you express them as the "coordinates" of that point. in this case  (2, -3)

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elena55 [62]
Do you know how to do it on your calculator?
6 0
3 years ago
Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
Please help Thank yourself
7nadin3 [17]

Answer:

75°

Step-by-step explanation:

There are 180° in a triangle, so using the ratios and the 180° setup an equation. Solve for x.

5x + 9x + 10x = 180

24x = 180

24x/24 = 180/24

x = 7.5

To find the largest angle measure, use 10x since 10 is bigger than 5 and 9.

10x

10(7.5)

75°

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Kitty [74]

Answer: its the same amount

Step-by-step explanation:

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2 years ago
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Answer: y=-8/5x-4

Step-by-step explanation:

8x+5y=-20

-8x         -8x

5y=-8x-20

/5     /5

y=-8/5x-4

4 0
3 years ago
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