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german
3 years ago
15

Write an equation of the line that passes through the given point and is parallel to the graph of the given equation.

Mathematics
1 answer:
True [87]3 years ago
7 0
Question 1:

--------------------------------------------------------------------
Find Slope
--------------------------------------------------------------------
Equation: y = 5x - 2
Slope = 5
Slope of parallel line = 5

--------------------------------------------------------------------
Insert slope into the general equation y = mx + c
--------------------------------------------------------------------
y = 5x + c

--------------------------------------------------------------------
Find y-intercept
--------------------------------------------------------------------
At point (2, -1)
y = 5x + c
-1 = 5(2) + c
c = -1 - 10
c = -11

--------------------------------------------------------------------
Insert y-intercept into the equation
--------------------------------------------------------------------
y = 5x + c
y = 5x - 11

--------------------------------------------------------------------
Answer: y = 5x - 11
--------------------------------------------------------------------

Question 2:

--------------------------------------------------------------------
Find Slope
--------------------------------------------------------------------
y = 9x 
Slope = 9 
Slope of the parallel line = 9

--------------------------------------------------------------------
Insert slope into the equation y = mx + c
--------------------------------------------------------------------
y = 9x + c

--------------------------------------------------------------------
Find y-intercept
--------------------------------------------------------------------
y = 9x + c
At point (0, 5)
5 = 9(0) + c
c = 5

--------------------------------------------------------------------
Insert y-intercept into the equation
--------------------------------------------------------------------
y = 9x + c
y = 9x + 5

--------------------------------------------------------------------
Answer: y = 9x + 5
--------------------------------------------------------------------
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Answer: (13.28\%,\ 18.72\%)

Step-by-step explanation:

Given : A random sample of 700 home owners in a particular city found 112 home owners who had a swimming pool in their backyard.

i.e. n= 700 and x= 112

Sample proportion : \hat{p}=\dfrac{x}{n}=\dfrac{112}{700}=0.16

z-value for 95% confidence interval : z_c=1.960

Now, the 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard will be :-

\hat{p}\pm z_c\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

=0.16\pm (1.96)\sqrt{\dfrac{0.16(1-0.16)}{700}}

=0.16\pm (1.96)(0.013856)\\\\\approx 0.16\pm0.0272\\\\ =(0.16-0.0272,\ 0.16+0.0272)=(0.1328,\ 0.1872)=(13.28\%,\ 18.72\%)

Hence, 95% confidence interval for the true percent of home owners in this city who have a swimming pool in their backyard : (13.28\%,\ 18.72\%)

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Four less than the quotient of a number and 4 is 14. What is the number? Let n be the unknown number.
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So the equation is n/4-4=14
then you +4 to both sides 
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then to check your work
72/4-4=14
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