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3241004551 [841]
3 years ago
8

1. The rent of a condo unit was ₱1,200.00 for one night, to be shared equally by a group of female friends, who will be having t

heir get together in the condo unit. At the last minute, four people decided not to go to the party, thus raising the cost to each girl by ₱400.00. How many girls attended the get-together?
(With Solutions Please)
Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Answer:

6 girls were there are first

Step-by-step explanation:

use trial and error. divide 1200 by a random number like 10, and see how much they each had to pay. If we guessed 10, then each girl would hypothetically pay 120 pounds. If four girls left, then 1200/6 would be 200 pounds. there was only a 60 pound increase here, not a 400 pound one.

I checked 1200/6 which equals 200 pounds per girl. If 4 girls left, then it would be 600 pounds for the 2 remaining girls. the rent increased from 200 to 600 which is a 400 pound increase.

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Solve for x. |4x - 5| > 7
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Answer:

x>3

Step-by-step explanation:

|4x-5|>7

4x -5>7

4x >7+5

4x /4>12/4

x >3

solution set={4,5,6,---}

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3. List 3 question that will help you analyse the effect on the accounting equation
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What is the quotient of 2/3 and 5/6
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4/5 is the quotient or the answer
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Least common denominator of 7/8 and 5/12
oksano4ka [1.4K]

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24

Step-by-step explanation:

24 is the lowest number 8 and 12 have in common

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Consider a set of one-dimensional points: 6, 12, 18, 24, 30, 42, 48.
Vinvika [58]

Answer:

1) With initial centroids 10-40, final clusters are

first cluster (6,12,18,24,30)

second cluster (42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 378

2) With initial centroids 10-20, final clusters are

first cluster (6,12,18,24)  

second cluster (30,42,48)

And the Sum of Squared Errors (SSE) for the clustering result is 348

Step-by-step explanation:

K-means works as follows

  • the points will be clustered according to their distance to the centroids.
  • Then centroids are updated as the cluster means.
  • This process continues until clusters doesn't change anymore

1)  <u><em>initial centroids</em></u> 10-40

first cluster (6,12,18,24)  mean:15

second cluster (30,42,48) mean:40

<u><em>new centroids</em></u> 15-40

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

<u><em>final centroids</em></u> 18-45

first cluster (6,12,18,24,30) mean:18

second cluster (42,48) mean:45

Sum of Squared errors = (18-6)^{2}+(18-12)^{2}+(18-18)^{2}+(18-24)^{2}+(18-30)^{2}+(45-42)^{2}+(45-48)^{2}=378

2)<u><em>initial centroids</em></u> 10-20

first cluster (6,12)  mean:9

second cluster (18,24,30,42,48)  mean:32.4

<u><em>new centroids</em></u> 9-32.4

first cluster (6,12,18) mean:12

second cluster (24,30,42,48) mean:36

<u><em>new centroids</em></u> 12-36

first cluster (6,12,18,24) mean:15

second cluster (30,42,48) mean:40

<u><em>final centroids</em></u> 15-40

first cluster (6,12,18,24) mean:15  

second cluster (30,42,48) mean:40

Sum of Squared errors = (15-6)^{2}+(15-12)^{2}+(15-18)^{2}+(15-24)^{2}+(40-30)^{2}+(40-42)^{2}+(40-48)^{2}=348

6 0
3 years ago
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