Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
X= -2 because I love school soooo much
False.
Right triangles do not have to be congruent.
:)
X^2-x-11=-x-7
X^2-11=-7
X^2=4
X=2 (4 was reduced to 2 after the equation was square rooted)
Pls give brainliest so close to ranking up
Answer:
<h2>
62.832 mi.²</h2><h2>
</h2>
Step-by-step explanation:
surface area = 2πrh + 2πr²
where r = 2 miles radius
h = 3 miles
<u>plugin values into the formula</u>
surface area = 2πrh + 2πr²
= 2π (2) 3 + 2π (2)²
= 37.699 + 25.133
= 62.832 mi.²
