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const2013 [10]
3 years ago
13

Find solution to the system of linear equations. 3x1 + 6x2 = 2 , 9x1 + 12x2 = 1

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0

Answer:

x₁ = -1

x₂ = 5/6

Step-by-step explanation:

The equations of the given linear system are:

3x_1 +6x_2=2\\9x_1 +12x_2 = 1

Multiply the first equation by -2 and add it to the second one to solve for x₁:

-6x_1 -12x_2=-4\\9x_1 +12x_2 +(-6x_1 -12x_2)= 1-4\\3x_1=-3\\x_1=-1

Since we already know the value of x₁, simply replace it in the first equation  to solve for x₂:

3x_1 +6x_2=2\\x_2=\frac{2+3}{6} =\frac{5}{6}

The solution for the system is x₁ = -1 and x₂ = 5/6

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Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.
SCORPION-xisa [38]

Answer:

The solutions are x=-3,\:x=3

Step-by-step explanation:

To factor this cubic polynomial x^3+3x^2-9x-27 you must:

  • Group the polynomial into two sections

x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)

  • Factor out -9 from (-9x-27)

(-9x-27)=-9\left(x+3\right)

  • Factor out x^2 from (x^3+3x^2)

(x^3+3x^2)=x^2\left(x+3\right)

x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)

  • Factor out common term x+3

-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)

x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)

  • Factor x^2-9

x^2-9=\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)

x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0

  • Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}

The solutions are

x=-3,\:x=3

3 0
3 years ago
A salesperson earned a salary of $12000 per year plus 5% commission on sales of $100000. What is his total income
Papessa [141]

If im doing right....

100,000*.5=50,000

Then 12,000+50,000=62,000 per year.

-Seth


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A baker wanted to enter the apple pie
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Answer:

11 pies

Step-by-step explanation:

100-12=88

88/8=11

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Write 73% as a simplified fraction
Murrr4er [49]

Answer:

73/100

Step-by-step explanation:

73% = 73/100

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Helen plays basketball. For free throws, she makes the shot 78% of the time. Helen must now attempt two free throws. C = the eve
riadik2000 [5.3K]

Answer:

0.6708 or 67.08%

Step-by-step explanation:

Helen can only make both free throws if she makes the first. The probability that she makes the first free throw is P(C) = 0.78, now given that she has already made the first one, the probability that she makes the second is P(D|C) = 0.86. Therefore, the probability of Helen making both free throws is:

P(C+D) =  P(C) *P(D|C) = 0.78*0.86\\P(C+D) = 0.6708

There is a 0.6708 probability that Helen makes both free throws.

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