
Since, we know that in Elimination method we have to first the value of "x" or either "y". For that we have to multiply a number which makes the both equation's "x" or "y" equal so that we cut cancel it and find the solution.
Here's an example:
Like, in here
Equation 1: - 2x + 3y = 9
Equation 2: - 8x - 7y = 10
We can see that in "Equation 1" the first number is "- 2x" and in "Equation 2" the first number is "-8x". So, what we do in Elimination method is that we have to make the first number of both the equations equal or same.
Eg:
- 2x + 3y = 9.
- 8x + 7y = 10--(ii)
Now,we can see that in "Equation 2" the first number is "8x" whereas in "Equation 1" the first number is "-2x". We have to multiply with any number that makes the both the first number of equation is same.
So, I'm taking the number "4" to multiply it with equation 1, which gives us the result,

Now, we've subtract both the equation to get the results.

-4x^5 + 2x^4 + x^3 + 3x^2 + 9x
Hope this helps.
Hi there!
You need to prove that line segment DE ≅ GH.
You're given:
Line segment DJ ≅ line segment GJ;
E is the midpoint of line segment DF;
H is the midpoint of line segment GJ.
You can justify that line segment DE ≅ line segment GH with the midpoint definition, which is a point on a line segment that divides it into two equal parts. The two equal parts in this case are line segments DE and GH, so DE ≅ GH.
Please comment with <em></em>any questions!
Answer:
D
Step-by-step explanation:
The slope is 2/5 and the slope of the new line will be -5/2 because the negative reciprocal creates a perpendicular line. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.
(y--2)=-5/2(x-2)
y+2=-5/2x+10/2
y=-5/2x+5-2
y= -5/2x+3