Can you please help please please help me with this question i will give you a Brainiest

1) A train travels 25 miles in 1/5 of an hour whats the trains speed in miles per hour?

Radda [10]

Answer:

<em>Hope this helps! ↓</em>

Step-by-step explanation:

1.) 90 Km/h. Example: What is the speed of a cheetah that travels 112.0 meters in 4.0 seconds? ... Speed of the cheetah in miles per hour 28m 1 mile 3600 s 63 miles

2.) y=kx is the direct variation formula. Inserting the information and variables from this scenario we get h = kn.

12 = k*(10) First solve for 'k', the constant of proportionality by dividing by 10.

1.2 = k

Next write the equation using this k and the h & n.

h = 1.2*n

Now we want to find the height if we have 24 books so plug 24 in for n.

h = 1.2 * 24

h = 28.8 inches

3.) 10/3

4 0

3 years ago

Read 2 more answers

9/15 divided by 27/30 =

Tema [17]

When dividing two fractions, we flip the second fraction and multiply by it (that is, use the reciprocal).

$\frac{9}{15}$ ÷ $\frac{27}{30}$

= $\frac{9}{15}$ × $\frac{30}{27}$

You can either multiply top by top and bottom by bottom or you can simplify by dividing out common factors.

= $\frac{1}{1}$ × $\frac{2}{3}$

= $\frac{2}{3}$

4 0

3 years ago

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$