ASA, HL, and SAS.
AAS wouldn't work, and LA and LL don't exist
Hope this helps!
20) Answer is: x=76
21) Answer is x=15
Answer:
The 95% confidence interval of the true mean.
(29.4261 ,36.9739)
Step-by-step explanation:
<u>Step :- (i)</u>
Given sample size 'n' =15
sample of the mean x⁻ = 33.2
The standard deviation of the sample 'S' = 8.3
<u>95% of confidence intervals</u>
<u></u>
<u></u>
<u>Step:-(ii)</u>
<u>The degrees of freedom γ=n-1 = 15-1=14</u>
The tabulated value t = 1.761 at 0.05 level of significance.
now substitute all possible values, we get
![(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )](https://tex.z-dn.net/?f=%2833.2%20-%201.761%5Cfrac%7B8.3%7D%7B%5Csqrt%7B15%7D%20%7D%20%2C33.2%2B%201.761%5Cfrac%7B8%7D%7B%5Csqrt%7B15%7D%20%7D%20%29)
After calculation , we get
(33.2-3.7739 , 33.2+3.7739
(29.4261 ,36.9739)
<u>Conclusion</u>:-
the 95% confidence interval of the true mean.
(29.4261 ,36.9739)
Y=mx+b
m=slope
given
y=6x-9
m=6
the slope is 6