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Yuki888 [10]
4 years ago
8

Which graph represents a function?

Mathematics
1 answer:
MissTica4 years ago
3 0
The second to last one, looks like a really tall speed bump
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Find the present value PV of the given investment. (Round your answer to the nearest cent.) An investment earns 2% per year and
vazorg [7]
Let P = the PV (principal value).

n = 12, the monthly compounding interval
r = 2 = 0.02, the rate
nt = 20 months

The value if $20,000 after 20 months, therefore
P(1 + r/n)²⁰ = 20000
1.0339P = 20000
P = $19,344.86

Answer: PV = $19,344.86

6 0
4 years ago
On October 2, 1991 , the Japanese yen was worth .0075 united States . At that time how much was 450 yen worth in united States d
lesya [120]
In order to find out how much 450 yen was worth in U.S dollars, all you have to do is multiply 0.0075 by 450. 

0.0075 * 450 = 3.375 

Meaning that 450 yen at the time was worth approximately $3.40 when rounded.
8 0
3 years ago
How do you solve an equation.
Sindrei [870]
By adding, subtracting, multiplying or dividing numbers
3 0
4 years ago
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Please help me to solve the question. (chapter angle between two lines)​
dsp73

Answer:    \bold{x^2-\dfrac{181}{13}xy+12y^2=0}

<u>Step-by-step explanation:</u>

\tan \theta =\dfrac{y}{x}\quad \longrightarrow \theta=\tan ^{-1}\bigg(\dfrac{y}{x}\bigg)

\text{Given:}\quad \theta =\tan^{-1}\bigg(\dfrac{1}{13}\bigg)\quad \longrightarrow x=13,y=1

Insert x = 13 and y = 1:

x² + 2hxy + 12y² = 0

(13)² + 2(13)(1) + 12(1)² = 0

169 + 26h + 12 = 0

       26h + 181 = 0

                26h = -181

                    h=-\dfrac{181}{26}

\text{Insert:}\ h=-\dfrac{181}{26}

x^2 + 2\bigg(-\dfrac{181}{26}\bigg) xy + 12y^2 = 0

\bold{x^2 -\bigg(\dfrac{181}{13}\bigg) xy + 12y^2 = 0}

8 0
3 years ago
I need to know this problem
Vaselesa [24]
C jdixixizi disused is
7 0
4 years ago
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