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jeka94
3 years ago
15

Pic attached for further detail

Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0
I dont get what you asking
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Could someone pls help me with this question!!!
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15 weeks

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4 years ago
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How much chromium-51 will be left after 7 months?
Makovka662 [10]

Answer:

It seems there's more information in you question that you haven't posted.

7 months = 7 * (365/12) = 213 days

The half-life of chromium 51 is 27.7 days.

After 7 months, chromium 51 will have undergone 7.69 half-lives.

To solve for the ending amount we'll use the formula:

Ending Amount = Beginning Amount / 2^n where 'n' = # of half-lives

We'll say the beginning amount =1

Ending Amount = 1 / 2^7.69

Ending Amount = 0.0048426082

Basicaly if you started with 1 gram of chromium 51, after 7 months you would have 0.0048426082 grams.

Source: https://www.1728.org/halflife.htm

Step-by-step explanation:

6 0
3 years ago
Expand and Simplify (2x+1)(x-2)(x+3)
NeTakaya

(2x + 1)(x - 2)(x + 3) \\  = (2x  + 1)( {x }^{2}  + x - 6) \\  ={2x}^{3}  + 2 {x}^{2} -12x +  {x}^{2}  + x - 6 \\  = 2 {x}^{3}  + 3 {x}^{2}  - 11x - 6
hope this would help you
6 0
4 years ago
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