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Ierofanga [76]
3 years ago
11

which statement is not a step used when constructing an inscribed equilateral triangle. A keep your compass at the with equal to

the radius of the circle. B. place the compass on the point where the circle and radius intercept. C. swing an arch the length of the radius from the point on the circle D. connect the two circles together using the compass
Mathematics
1 answer:
djyliett [7]3 years ago
7 0

Answer: Connect the two circles together using the compass.

Steps to inscribe an equilateral triangle into a circle:

1. You are given a circle with the center marked.

2. Draw a radius of the circle using your straightedge.

3. Keep your compass open to the width of the radius and place it on the point where the radius and circle intersect.

4. Swing an arc the length of the radius that intersects the circle to the left of the radius originally drawn.

5. Keeping your compass at the same width, place it on the new intersection point you created in the previous step.

6. Continue this process until six points of intersection exist on the circle.

7. Connect together the first, third, and fifth intersection points.

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Travka [436]

-- "Perimeter" means all the way around, all four sides.

-- That's two lengths and two widths.

-- So one length and one width is half of the perimeter.

-- If the perimeter is 16-ft, then one length + one width is 8-ft.

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3 years ago
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Write an expression that is equivalent to 734+356 − 134 that uses addition instead of subtraction.
Readme [11.4K]

Answer:956= _+_

Step-by-step explanation:

Put the Equations together,

734+356-134=956

956 = ?

make any equation that would equal 956

Ex: 955+1=956.

(I wouldn't make it that easy tho lol teacher might not get fond of you)

I think this was the right way. If not, sorry!

6 0
3 years ago
Find all numbers whose absolute value is 2 .
Amiraneli [1.4K]
Absolute value of a real number, is the distance between that number and 0 on a number line. Therefore the absolute value of 2 is 2 and negative 2
6 0
3 years ago
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4 - x + <img src="https://tex.z-dn.net/?f=6%5E%7B2%7D" id="TexFormula1" title="6^{2}" alt="6^{2}" align="absmiddle" class="latex
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Answer:

x ≤ 19

Step-by-step explanation:

The instructions here are probably "solve for x."  Please include them.

4 - x + 6^2 ≥  21

becomes 4 - x + 36 ≥  21

Now combine like terms.  4 and 36 combine to 40:  40 - x ≥ 21, and so:

19 - x ≥ 0

Adding x to both sies results in

x ≤ 19

Please, include the instructions when you post a question.  Thanks.

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Answer:

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Step-by-step explanation:

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