All categories

3 years ago

Please answer it for me or show me how to do it? I will mark you branliast answer !!

Mathematics

1 answer:

klasskru [66]3 years ago

7 0

Answer:

Step-by-step explanation:

If HI and IJ are both the same and meet at the same point, the triangles would be the same.

You might be interested in

Lakita wants to go to trade school and study electronics for a two-year program. Her tuition and books will cost about $5,500 pe

pshichka [43]

Answer:

Step-by-step explanation:

Step one:

let us first compute the tuition and books for the two years

we are told that the tuition is $5,500 per year

For the two years,the tuition will be 5,500*2= $11,000

Step two:

we need to calculate the cost of transportation for the two years also

in two years there are 24 months

if Lakita will spend $100 per months

then in 24 months Lakita will spend= 24*100= $2400

Hence her education cost her in total is

=$11,000+$2400

=$13,400

8 0

2 years ago

. 　　　。　　　　•　　ﾟ　　。　　. 　　　.　　　　　.　　　　　。　　。　. 　 .　　。　　　　　 ඞ 。 . 　　 • 　　　　• 　　ﾟ　　 villain deku was An Impostor.　。　. 　　'　　　 1 I

Pie

Answer:

Step-by-step explanation:

:o who is it?!?!?!

3 0

3 years ago

Read 2 more answers

Which of these expressions shows a correct way to set up the slope formula for the line that passes through the points (5, 0) an

vaieri [72.5K]

Answer:

Step-by-step explanation:

its c because if we input the numbers into the slope formula y2 - y1 over x2 - x1 it equals -6 - 0 over 6 - 5

3 0

3 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

3 years ago

Write 27% as a fraction.

Reil [10]

Answer:

27/100

Step-by-step explanation:

27%= 0.27= 27/100 which cannot be reduced

5 0

3 years ago

Read 2 more answers