3 years ago

Which products are negative?

2 answers:

8 0

A,B,and C because in when multiplying or dividing, + and - will be negative and if they are + and + or, - and - then the answer will be positive.

ipn [44]3 years ago

8 0

All of them accept for d

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Please answer this in two minutes

noname [10]

Answer:

60°

Step-by-step explanation:

tan 60 = sin 60 / cos 60

= [(root 3) / 2] ÷ [1/2]

= root 3

[sin 60 = (root 3) / 2 ; cos 60 = 1 / 2 ]

3 0

3 years ago

May you please help me for part b for brainliest,

olya-2409 [2.1K]

Answer:

Very certain it is C

Step-by-step explanation:

There are no points on the graph line itself so I cannot really confirm this but i am 70% sure

7 0

2 years ago

Someone please help me quick!

Inessa [10]

Can you explain the question in words please?

5 0

2 years ago

(3x+2) and (5x-6) solve for x

HACTEHA [7]

Answer:

x=3X 2 + 5x -6

Step-by-step explanation:

3X2 + 5X-6= 3X2 + 5X 6

X=3X2 +5X -6

6 0

3 years ago

If a,b,c,d, and e are non negative such that x^6-289x^4-x^2+289=(x-a)(x+b)(x_c)(x+d)(x^2+ex+1), what is the value of a+b+c+d+e?

Irina18 [472]

Answer:

Step-by-step explanation:

Hello,

If $X=x^2$ it becomes

$X^3-289X^2-X+289=(X^2-1)(X-289)$

and $289=17^2$

$X^2-1=(X-1)(X+1)=(x^2-1)(x^2+1)=(x+1)(x-1)(x^2+1) \\\\x^2-289=x^2-17^2=(x-17)(x+17)$

So,

$x^6-289x^4-x^2+289=(x^2-1)(x^2+1)(x^2-289)=(x-1)(x+1)(x+17)(x-17)(x^2+1)$

a = 1

b = 1

c = 17

d = 17

e = 0

Then a + b + c + d + e = 36

Thanks

3 0

2 years ago