<u>there </u><u>a</u><u>r</u><u>e</u><u> </u><u>3</u><u>1</u><u>4</u><u>.</u><u>5</u><u> </u><u>b</u><u>o</u><u>y</u><u>s</u><u> </u><u>in the school </u><u>.</u>
Answer:
Solution given
let boys be x and girls be y.
now
according to the question;
x+y=575
and
y=x-54
substituting value of y in equation 1.
x+x-54=575
2x=575+54
x=629/2
x=314.5
Sin³(x)cos⁴(x) = sin(x)[cos⁴(x) - cos⁶(x)]
sin(x) sin(x)
sin²(x)cos⁴(x) = cos⁴(x) - cos⁶(x)
sin²(x)cos⁴(x) = cos⁴(x)[1] - cos⁴(x)[cos²(x)]
sin²(x)cos⁴(x) = cos⁴(x)[1 - cos²(x)}
cos⁴(x) cos⁴(x)
sin²(x) = 1 - cos²(x)
+ cos²(x) + cos²(x)
1 = 1
One hundred nineteen million and three
Find the number in the tenth place 0 and look one place to the right for the rounding digit 9. Round up if this number is greater than or equal to 5 and round down if it is less than 5.
Answer: 0.1
Answer:
5
Step-by-step explanation:
p=(8)-3
p=5