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3 years ago

Round 0.0936 round to the nearest tenth

1 answer:

4 0

Find the number in the tenth place 0 and look one place to the right for the rounding digit 9. Round up if this number is greater than or equal to 5 and round down if it is less than 5.

Answer: 0.1

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Use unit multipliers to convert 20 cubic miles to cubic inches

Artemon [7]

Answer:

20 cubic miles = 5.0872E+15 cubic inches

Step-by-step explanation:

it's a big number. hope this helps!

8 0

2 years ago

Yolanda paid for her movie ticket using 28 coins, all nickels and quarters. The ticket cost $4. Which system of linear equations

Anvisha [2.4K]

Answer:

n + q = 28 0.05n + 0.25q = 4

3 0

3 years ago

Read 2 more answers

Solve for x…..…………………

anzhelika [568]

Answer:

x = 11

Step-by-step explanation:

From the diagram, we find,

(2x - 16) + (x - 8) = 9

=> 2x - 16 + x - 8 = 9

=> 2x + x - 16 - 8 = 9

=> 3x - 24 = 9

=> 3x = 9 + 24

=> 3x = 33

=> x = 33/3

=> x = 11

8 0

2 years ago

Read 2 more answers

Marge purchased bicycle helmets and tire pumps. Each helmet cost $12.00 and each pump cost $8.00. She purchased a total of 18 it

algol [13]

Answer:

Step-by-step explanation:

Let the no. of helmet be x

cost of 1 helmet = $12.00

cost of x helmet = $12.00*x = $12x

Let the no. of tire pumps be y

cost of 1 tire pumps = $8.00

cost of x tire pumps = $8.00*y = $8y

Given that total no. of helmet and pump is 18

thus

x + y = 18

y = 18-x

also given

total money spent is $188

thus

12x+8y = 188

using y = 18 - x

we have

12x + 8(18-x) = 188

=> 12x+ 144 - 8x = 188

=> 4x = 188-144 = 44

=> x = 44/4 = 11

Thus, no of helmet bought by Margo is 11.

7 0

2 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$