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Arada [10]
3 years ago
7

A kite with a string 50 meters long makes an angle of elevation of 58o with the ground, assuming the string is straight, how hig

h is the kite? Round your answer to the nearest tenth of a foot.
Mathematics
1 answer:
joja [24]3 years ago
4 0
String is the hypotenuse
angle is 58 degrees
sine (58) = height / 50
height = 50 * .84805
height = <span> <span> <span> 42.4025 </span> </span> </span>


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Calculate the following scenario for a simple interest loan.
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<h3>What is simple interest?</h3>

Simple interest is a method of calculating interest on an amount for n period of time with a rate of interest of r. It is calculated with the help of the formula,

SI = (PRT)/100

where SI is the simple interest, P is the principal amount, R is the rate of interest, and T is the time period.

Given the following details about the simple interest loan as,

Principal amount, P = $3,000

Interest rate, r = 15%

Number of instalments = 12

Since there are 12 instalments each for a month, therefore, the time period for which the loan was there is 1 year.

Now, the interest for 1 year will be,

Interest amount = ($3,000 × 1 × 15)/100

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Amount needed = $3,000 + $450

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Monthly payment = $3,450/12 = $287.5

Hence,  the amount of monthly payments is $287.5.

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What is 27/4 as a mixed number?
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Answer:

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Step-by-step explanation:

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=>\ \dfrac{dy}{dt}\ =\ -ycost

=>\ \dfrac{dy}{y}\ =\ -cost dt

On integrating both sides, we will have

  \int{\dfrac{dy}{y}}\ =\ \int{-cost\ dt}

=>\ logy\ =\ -sint\ +\ c

Hence, the solution of given differential equation can be given by

logy\ =\ -sint\ +\ c.

2. Given differential equation,

    \dfrac{dy}{dt}\ -\ 2ty\ =\ t

=>\ \dfrac{dy}{dt}\ =\ t\ +\ 2ty

=>\ \dfrac{dy}{dt}\ =\ 2t(y+\dfrac{1}{2})

=>\ \dfrac{dy}{(y+\dfrac{1}{2})}\ =\ 2t dt

On integrating both sides, we will have

   \int{\dfrac{dy}{(y+\dfrac{1}{2})}}\ =\ \int{2t dt}

=>\ log(y+\dfrac{1}{2})\ =\ 2.\dfrac{t^2}{2}\ + c

=>\ log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

Hence, the solution of given differential equation is

log(y+\dfrac{1}{2})\ =\ t^2\ +\ c

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