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3 years ago

Determine the total number of roots of each polynomial function.

Mathematics

2 answers:

Vera_Pavlovna [14]3 years ago

4 0

For this case we have the following function:

$f (x) = 3x ^ 6 + 2x ^ 5 + x ^ 4 - 2x ^ 3$

The first thing that we must observe to know the amount of roots that the function has, is the degree of the greatest exponent.

We observe that the degree of the greatest exponent is equal to 6.

Therefore, the function has 6 roots.

The roots can all be real with different multiplicities.

There may also be real roots and complex roots.

Answer:

The total number of roots for the given polynomial function is 6.

Kitty [74]3 years ago

3 0

Base on my research there are ways to get the number of roots. If you are looking for negative roots and even the positive one has their own ways. But in this problem, we just need to determine the total number of roots of a polynomial. In determining the total number of roots, you just need to find the degree of the polynomial function. The degree refers to the highest exponent of the polynomial. Therefore, in the function given, 6 is the degree of the polynomial function. The total number of roots is 6.

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3 years ago

5.Richard Miyashiro purchased a condominium and obtained a 30-year loan of $196,000 at an annual interest rate of 8.20%. (Round

GREYUIT [131]

Answer:

5 a) PMT=$1,465.60

b) Total Payments=$527,616

c) Total Interest=$331,616

6a) Interest=$1,079.93

b) Principal=$584.07

Step-by-step explanation:

a. Given the loan amount is $196,000, annual rate is 8.2% and the loan term is 30 years.

-The monthly mortgage payment can be calculated as follows:

$PMT=A(\frac{(r/n)}{1-(1+\frac{r}{n})^{-nt}})$

Where:

PMT is the monthly mortgage payment
r is the annual interest rate
n,t is the number of annual payments and time in years respectively

-We substitute to solve for PMT:

$PMT=A(\frac{(r/n)}{1-(1+\frac{r}{n})^{-nt}})\\\\=196000[\frac{(0.082/12)}{1-(1+\frac{0.082}{12})^{-12\times30}}]\\\\=\$1,465.60$

Hence, the monthly mortgage payment is $1,465.60

b. The total number of payments is obtained by multiplying the total number of payments by the amount of each payment:

$\sum(payments)=PMT\times nt\\\\=1465.60\times 12\times 30\\\\=\$527,616.00$

Hence, the total amount of payments is $527,616

c. The amount of interest paid over the loan's term is obtained by subtracting the principal loan amount from the total payments made:

$Interest=Payments-Principal\\\\=527,616.00-196,000.00\\\\=\$331,616$

Hence, an interest amount of $331,616 is paid over the loan's term.

6 a) We first obtain the effective loan amount by subtracting the down-payment:

$Loan \ Amount= Regular \ Price -Downpayment\\\\=205700-0.1(205700)\\\\=\$185,130$

The interest paid on the first mortgage payment is calculated as below:

$I=\frac{r}{n}\times P\\\\I=Interest\\r=interest \ rate\\n=Payments \ per \ year\\P=Outstanding \ loan \ balance\\\\\therefore I=\frac{0.07}{12}\times 185130\\\\=\$1,079.93$

Hence, the amount of interest in the first payment is $1,079.93

b. The amount of principal repaid is obtained by subtracting the interest amount from the monthly mortgage payments;

$Principal \ Paid=PMT-Interest\\\\PMT=A[\frac{(r/n)}{1-(1+\frac{r}{n})^{-nt}}]\\\\=185130[\frac{(0.07/12)}{1-(1+\frac{0.07}{12})^{-180}}\\\\=1664.00\\\\\\Principal \ Paid=1664.00-1079.93\\\\=\$584.07$

Hence, the amount of principal applied is $584.07

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