Given:
Total number of students = 27
Students who play basketball = 7
Student who play baseball = 18
Students who play neither sports = 7
To find:
The probability the student chosen at randomly from the class plays both basketball and base ball.
Solution:
Let the following events,
A : Student plays basketball
B : Student plays baseball
U : Union set or all students.
Then according to given information,




We know that,



Now,





It means, the number of students who play both sports is 5.
The probability the student chosen at randomly from the class plays both basketball and base ball is


Therefore, the required probability is
.
642.2 is the answer if you multiply 3.8x169
Answer:
77.4 el valor del ipod con el 40% de descuento
vStep-by-step explanion
40%/ 100%= 0.4
0.4x129= 51.6( la cantidad que nos van a descontar)
129-51.6=77 .4 es el valor del ipod con el 40% de descuento
Answer:
10/21
Step-by-step explanation:
First you reduce 3000/6300 to 30/60 and then reduce it to 10/21