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Kitty [74]
3 years ago
14

Consider the area shown below. The top curve (in blue) is y=cuberoot(x) and the bottom curve (in red) is y=x^3, and we have used

the notation Dy for delta y.
Mathematics
1 answer:
stira [4]3 years ago
6 0
The top curve is
y = √x
The bottom curve is
y = x³

We are to find the area between the two curves, the limits are 0 and 1
A = ∫(x³ - √x)dy from 0 to 1
A = x⁴/4 - (1/2)/√x |from 0 to 1
A = 0.25 square units
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Exact decimals of 7 5/6​
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Which two terms in (3+14) +27 could you add to get a multiple of ten? ​
Aleksandr-060686 [28]

Answer:

3 and 27

Step-by-step explanation:

<u>Step 1:  Determine which two terms we can use</u>

We have the following numbers to choose from:  3, 14, 27

Adding two numbers to get a multiple of ten means that the number that we come up with needs to be divisible by ten.  For example:  20, 30, 50, 100 are all multiples of ten.

In this example the only one that would add up to create a multiple of ten is 27 and 3 which would give us 30 which is a multiple of 10.

Answer: 3 and 27

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2 years ago
Which number line represents all of the values of x for the equation x2 = 16? A number line is shown from negative 10 to 0 to po
Svetllana [295]
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4 0
3 years ago
A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.
zmey [24]

Answer:

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation  

\bar X=2.2 represent the sample mean

s=0.29 represent the sample standard deviation

n=40 sample size  

\mu_o =2.1 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.1  

Alternative hypothesis:\mu > 2.1  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0
3 years ago
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