The top curve is y = √x The bottom curve is y = x³
We are to find the area between the two curves, the limits are 0 and 1 A = ∫(x³ - √x)dy from 0 to 1 A = x⁴/4 - (1/2)/√x |from 0 to 1 A = 0.25 square units
Wait what's the question tho? is it if this point is on the line? cause it's not -y=mx+b 3=-6(6)-3 -3=-36-3 -3 does not equal -39 hence, point is not on the line
