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2 years ago

When you type in a question...it what pops up the answer???

Mathematics

1 answer:

Serhud [2]2 years ago

7 0

If what you mean is the website then the many other users (like myself) answer said question.

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Needing help with problems 1,2,3. and 4

Marrrta [24]

1 and 2 are 1/4 and 90 degrees
3. 360 degrees and 4/4
4. 180 degrees and 2/4

4 0

2 years ago

Write an equation for the following tile pattern. Figure 2 Figure 3 Figure 4

oksano4ka [1.4K]

Answer:

The general equation following the pattern becomes is 7 + (n - 1)×2

Where, n = The figure number - 1

Step-by-step explanation:

The pattern in the question can be described as follows;

Figure 2 = (5 + 2) squares boxes = 7 squares boxes

Figure 3 = (5 + 2 + 2) squares boxes

Figure 4 = (5 + 2 + 2 + 2) squares boxes

Therefore, the number of squares boxes per figure, form an arithmetic progression (a + (n - 1)d) with the first term a = 7, the common difference d = 2, and the n = the nth term of the series, such that the general equation following the pattern becomes;

7 + (n - 1)×2.

3 0

2 years ago

Use the quadratic formula to solve the equation X^2+9X+20=0

lions [1.4K]

Answer:

x=-4

x=-5

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$

Hence, confirmed

6 0

3 years ago

Geometry please help if you can

erik [133]

$Area \: of \: sundial:3.14 \times \frac{ {8}^{2} }{4} = 3.14 \times 16 = 50.24 \: {ft}^{2} \\ Area \: of \: one \: section: \frac{50.24}{8} = 6.28 \: {ft}^{2}$

6 0

2 years ago