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3 years ago

Area of a composite figure

Mathematics

1 answer:

Lana71 [14]3 years ago

7 0

Answer:

55cm I am not sure buut

Step-by-step explanation:

20+20+10+5

40+15

55cm

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Help me

butalik [34]

Answer:

D. Tenths

Step-by-step explanation:

Because when you go behind the decimal, it starts out with tenths, then hundredths, and then thousandths. And 6 in the 1st spot behind the decimal so it's tenths.

hope I helped.

6 0

3 years ago

ILL GIVE BRAINLIEST... HURRY PLZ

Alexeev081 [22]

12 Pairs

4 pairs = 8

2 pairs = 4

8 + 4 = 12

If you need total socks, there's 24 total

7 0

3 years ago

the density of a certain material is such that weighs 6900 grams for every 4.5 quarts of volume express this density in pounds p

dlinn [17]

Answer:

$d=101.4\ \text{pounds}/\text{feet}^3$

Step-by-step explanation:

Given that,

Mass of material, m = 6900 grams

Volume of the material, V = 4.5 quarts

We need to find the density in pounds per cubic foot

We know that,

1 pound = 453.59 grams

⇒ 6900 grams = 15.21 pounds

Also, 1 cubic foot = 29.92 quarts

4.5 quart = 0.15 feet³

Density = mass/volume

$d=\dfrac{15.21\ \text{pounds}}{0.15\ \text{feet}^3}\\\\d=101.4\ \text{pounds}/\text{feet}^3$

Hence, the density of the material is $101.4\ \text{pounds}/\text{feet}^3$

3 0

4 years ago

6 3/5-2 4/5=?<br> Show how you got the answer

Viktor [21]

Hello there,

Okay so the question is asking us to subtract the two mixed numbers, 6 3/5 - 2 4/5, from each other...

The first step would be to change the mixed numbers to improper fractions:

6 3/5 as improper fraction would be 33/5
2 4/5 as improper fraction would be 14/5

Now we need to make sure that the denominators are the same and in this case they are.

Simply subtract 14 from 33 and you would get 19 and the denominator stays the same so you would get 19/5.

Now turn 19/5 into a mixed number and you would get 3 4/5

The answer to the 6 3/5 - 2 4/5 would be 3 4/5.

Hope I helped,

Amna

7 0

3 years ago

Describe how to transform:

Anna71 [15]

Answer:

$x^\frac{35}{6}$

Step-by-step explanation:

The expression to transform is:

$(\sqrt[6]{x^5})^7$

Let's work first on the inside of the parenthesis.

Recall that the n-root of an expression can be written as a fractional exponent of the expression as follows:

$\sqrt[n]{a} = a^{\frac{1}{n}}$

Therefore $\sqrt[6]{a} = a^{\frac{1}{6}}$

Now let's replace $a$ with $x^{5}$ which is the algebraic form we are given inside the 6th root:

$\sqrt[6]{x^5} = (x^5)^{\frac{1}{6}}$

Now use the property that tells us how to proceed when we have "exponent of an exponent":

$(a^n)^m= a^{n*m}$

Therefore we get: $(x^5)^{\frac{1}{6}}=x^{\frac{5}{6}}}$

Finally remember that this expression was raised to the power 7, therefore:

$[tex](\sqrt[6]{x^5})^7=(x^\frac{5}{6})^7=x^\frac{35}{6}$ [/tex]

An use again the property for the exponent of a exponent:

8 0

3 years ago

Area of a composite figure​

Area of a composite figure