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wlad13 [49]
3 years ago
6

One positive number is five times another number is the difference between the two numbers is 1676 find the numbers

Mathematics
2 answers:
jonny [76]3 years ago
7 0
The two numbers are X=-419 X=-2095
AleksAgata [21]3 years ago
4 0

Answer:

The two numbers are -419 and -2095.

Step-by-step explanation:

5x=y

x-y=1676

----------------

x-5x=1676

-4x=1676

x=1676/-4

x=-419

5(-419)=y

y=-2095

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Start by laying out 7 tiles, and then adding 3. Whatever that number of tiles is equals x.

x = 10

10 - 3 = 7

7 0
2 years ago
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vova2212 [387]
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Solve for x if log(2x-7) = 0
schepotkina [342]

Answer:

x=4

Step-by-step explanation:

log(2x-7) = 0

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4 0
2 years ago
Suppose that the trace of a 2×2 matrix a is tr(a)=15 and the determinant is det(a)=50. find the eigenvalues of
IrinaK [193]
Recall that the characteristic polynomial of a 2x2 matrix \mathbf A=\begin{bmatrix}a&b\\c&d\end{bmatrix} is

\det(\mathbf A-\lambda\mathbf I)=\begin{vmatrix}a-\lambda&b\\c&d-\lambda\end{vmatrix}=(a-\lambda)(d-\lambda)-bc=\lambda^2-(a+d)\lambda+(ad-bc)

but \det(\mathbf A)=ad-bc and \mathrm{tr}(\mathbf A)=a+d, so the characteristic polynomial for \mathbf A is

\lambda^2-\mathrm{tr}(\mathbf A)\lambda+\det(\mathbf A)

We're given that the trace is 15 and determinant is 50, so the characteristic polynomial for the matrix in question is

\lambda^2-15\lambda+50

and the eigenvalues are those \lambda for which the characteristic polynomial evaluates to 0.

\lambda^2-15\lambda+50=(\lambda-5)(\lambda-10)=0\implies\lambda=5,\lambda=10
5 0
2 years ago
A racing bicycle with a cash price of 900 at at 90 down down and 40.50 per month for 24 months ​
Sav [38]

Answer:

1062 for 24 monthly payments plus 90$ down payment

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90+40.50x               x=24 months

40.5 x 24 = 972

+90

------------------------

1062

3 0
3 years ago
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