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MAVERICK [17]
4 years ago
14

A national park covers 212375 acres

Mathematics
1 answer:
Gala2k [10]4 years ago
5 0
What is the question

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Ricky withdrew a total of $175 from his bank account over 5 days. He withdrew the same amount each day. By how much did the amou
kifflom [539]

Answer:

$35

Step-by-step explanation:

175/5 = 35

have a nice day! (maybe get this double checked in case I did it wrong :D)

8 0
3 years ago
7-x/3=-1-x/8 I'm in 8th grade and I can't figure this out​
antiseptic1488 [7]

Answer: x = 38.4

Step-by-step explanation:

7-x/3 = -1-x/8

1. Add 1 to both sides

8-x/3 = -x/8

2. Add x/3 to both sides

8 = x/3 - x/8

3. Multiply x/3 by 8/8 and x/8 by 3/3 to get the same number under the quotient

8 = 8x/24 - 3x/24

4. calculate the difference between 8x/24 - 3x/24

8 = 5x/24

5. Multiply both sides by 24/5, and there is the answer

38.4 = x

7 0
3 years ago
Can someone help? I am in need
kumpel [21]
Assumed Correlation Value:
r1 = -0.5
r2 = 0.25
r3 = 0.90
r4 = 1


therefore,

r1 < r2 < r3 < r4

Letter A
4 0
3 years ago
Use the common denominator to find -2/3 + -4/5​
Svetlanka [38]

Answer:

-22/15

Step-by-step explanation:

Okay, so, find a common multiple of 3 and 5. best way to find one is to multiply them. 3 x 5= 15. Now you have to make the numerators equivalent.

-2/3 = -10/15

-4/5 = -12/15

-10+-12=-22

Answer:-22/15

5 0
3 years ago
An electronics company just finished designing a new tablet computer and is interested in estimating its battery-life. A random
Alika [10]

Answer:

6 \pm 2.861(0.3354)

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 20 - 1 = 19

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.995. So we have T = 2.861.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.861\frac{1.5}{\sqrt{20}} = 2.861(0.3354)

In which s is the standard deviation of the sample and n is the size of the sample.

The format of the confidence interval is:

S_{M} \pm M

In which S_{M} is the sample mean

So

6 \pm 2.861(0.3354)

7 0
3 years ago
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