Answer: 11 square root 57
Step-by-step explanation:
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
1/2 would be in between 0 and 1. The fraction 4/2 is actually 2, so it would just be plotted on the number 2 on the number line. 5/2 is reduced to 2.5, therefore it goes in between 2 and 3.
Answer:
42,183
Step-by-step explanation:
We will use the Continuous Compounding Interest since a regular interval was not stated.
P(t) = Pe^(rt)
We will plug in the variables to the formula
P(t) = 31250 * e^(.12 * 2.5)
We can simplify and evaluate the compound interest.
P(t) = 42183.08
110x4=440 beats in 4 minutes
