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jok3333 [9.3K]
2 years ago
12

How to simplify 5+4·(8-6)2 power

Mathematics
1 answer:
allsm [11]2 years ago
3 0
5+4×(8-6) to the 2nd 9×2 to the 2nd equals 9×4 which then equals 36.
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Help Help Help please!
sergij07 [2.7K]

Answer:

this might take a while

7 0
3 years ago
Y= -4/3x - 5/2<br><br>y-intercept:<br><br>slope:​
CaHeK987 [17]

Answer:the answer is Y= -4/3x - 5/2

Step-by-step explanation:

3 0
3 years ago
Let f(x) = 6x-5 and g(x) = 2x-1. Find f • g
tankabanditka [31]

Hi

(6x-5) (2x-1) =  12x²-6x-10x+5 =  12x²-16x +5

3 0
3 years ago
In front of a store, there is a row of parking spaces. Cars park parallel to one another, with the front of each car facing the
Gelneren [198K]

The width used for the car spaces are taken as a multiples of the width of

the compact car spaces.

Correct response:

  • The store owners are incorrect
<h3 /><h3>Methods used to obtain the above response</h3>

Let <em>x</em><em> </em>represent the width of the cars parked compact, and let a·x represent the width of cars parked in full size spaces.

We have;

Initial space occupied = 10·x + 12·(a·x) = x·(10 + 12·a)

New space design = 16·x + 9×(a·x) = x·(16 + 9·a)

When the dimensions of the initial and new arrangement are equal, we have;

10 + 12·a = 16 + 9·a

12·a - 9·a = 16 - 10 = 6

3·a = 6

a = 6 ÷ 3 = 2

a = 2

Whereby the factor <em>a</em> < 2, such that the width of the full size space is less than twice the width of the compact spaces, by testing, we have;

10 + 12·a < 16 + 9·a

Which gives;

x·(10 + 12·a) < x·(16 + 9·a)

Therefore;

The initial total car park space is less than the space required for 16

compact spaces and 9 full size spaces, therefore; the store owners are

incorrect.

Learn more about writing expressions here:

brainly.com/question/551090

5 0
2 years ago
A bag contains 42 red marbles, 6 white marbles, and 8 gray marbles. You randomly pick out a marble, record its color, and put it
Elanso [62]
For any single draw,

\mathbb P(\text{white})=\dfrac6{42+6+8}=\dfrac6{56}
\mathbb P(\text{gray})=\dfrac8{42+6+8}=\dfrac8{56}

Drawing a white marble or a gray marble are disjoint events; only one of them can happen. So

\mathbb P(\text{white or gray})=\mathbb P(\text{white})+\mathbb P(\text{gray})-\underbrace{\mathbb P(\text{white and gray})}_0
\mathbb P(\text{white or gray})=\dfrac6{56}+\dfrac8{56}=\dfrac{14}{56}

Out of 224 draws, you should expect \dfrac{14}{56}\times224=56 of the marbles to be either white or gray.
6 0
3 years ago
Read 2 more answers
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