Given: sin (A) = 5/13, pi/2 < A < pi and tan (B) = - sqr root 13, pi/2 < B <. What is tan(A - B)? A. (5 + 12sqr root
13)/(12 - 5sqr root13) B. (12 - 5sqr root)/(5 + 12sqr root13) C. (12 + 5sqr root13)/(-5 + 12 sqr root13) D. (-5 + 12 sqr root13)/(12 + 5 sqr root13)
1 answer:
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Answer:
96 sq. cm.
Step-by-step explanation:
A "kite" has 2 diagonals, which are the "width" and "height" of the kite.
Using diagonals, the area of a kite is given by
Where
A is the area
p,q are the width and height, respectively
From the problem given, p is 12 and q is 16, so the area is:
Thus, the area is 96 sq. cm