Given: sin (A) = 5/13, pi/2 < A < pi and tan (B) = - sqr root 13, pi/2 < B <. What is tan(A - B)? A. (5 + 12sqr root
13)/(12 - 5sqr root13) B. (12 - 5sqr root)/(5 + 12sqr root13) C. (12 + 5sqr root13)/(-5 + 12 sqr root13) D. (-5 + 12 sqr root13)/(12 + 5 sqr root13)
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I have drawn the graphs.you can get from them,maybe turn left 2
