Question

10 points please help​

Answer 1

Answer:

$\frac{14}{55}$

Step-by-step explanation:

note that

n! = n(n - 1)(n - 2) .... × 3 × 2 × 1

Given

$\frac{8!9!}{5!12!}$

Cancel the terms from 8! ( 5 × 4 × 3 × 2 × 1 ) with the same terms from

5! ( 5 × 4 × 3 × 2 × 1 ) leaving

8 × 7 × 6 = 336 on the numerator

Similarly

Cancel the terms from 9! and 12!

leaving 12 × 11 × 10 = 1320 on the denominator, thus simplifies to

$\frac{336}{1320}$

= $\frac{14}{55}$