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2 years ago

Both roots of x^2 + Nx + 144 are equal to each other. Find all the possible values of N.

Mathematics

1 answer:

Amanda [17]2 years ago

6 0

Answer:

N=+24,-24

Step-by-step explanation:

Well this is a quadratic equation and we can make further deductions using it's discriminant

b²-4ac=0

N²-4(1×144)=0

N²-576=0

N²=576

N=√576

N=+24,-24

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Solve by the elimination method

Usimov [2.4K]

There is one solution. The solution of the system is (9,-5)

Option A is correct.

Step-by-step explanation:

We need to solve the system of equations by elimination method

$6x= 64+2y\\2x= -7-5y$

Rearranging the equations:

$6x-2y=64\,\,\,eq(1)\\2x+5y=-7\,\,\,eq(2)$

Eliminating y to find value of x:

Multiply eq(1) by 5 and eq(2) by 2 and add both equations:

$30x-10y=320\,\,\,\\4x+10y=-14\\--------\\34x=306\\x=\frac{306}{34}\\ x=9$

So, value of x= 9

Eliminating x to find value of y:

Multiply eq(1) by 2 and eq(2) by 6 and subtract both equations:

$12x-4y=128\\12x+30y=-42\\-\,\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\---------\\-34y=170\\y=\frac{170}{-34}\\ y=-5$

So, value of y = -5

There is one solution. The solution of the system is (9,-5)

Option A is correct.

Keywords: Solving system of equations

Learn more about Solving system of equations at:

#learnwithBrainly

5 0

3 years ago

Quadrilateral OPQR is inscribed inside a circle as shown below. What is the measure of angle Q? You must show all work and calcu

viktelen [127]

Hello,

Angles y and 3y+8 are supplementaries since the quadrilater is inscribed

y+3y+8=180
==>4y=172
==>y=43 (°)

8 0

3 years ago

Can you help me with this please???

Dahasolnce [82]

Answer:

Step-by-step explanation:

8 0

3 years ago

List the common multiple of 42 and 14 . Help plzzzz

Alborosie

The answer is 42,84,126 and so on.(you keep on adding 42)

3 0

3 years ago

The SAT Reasoning Test (formerly called the Scholastic Aptitude Test) is perhaps the most widely used standardized test for coll

slamgirl [31]

Answer:

The score is $x = 1884$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 1500$

The standard deviation is $\sigma = 300$

From the question we are told that the score follow a normal distribution

i.e $X \~ \ N( 1500 , 300)$

The proportion of score in the top 10% is mathematically

$P(X > x ) = P( \frac{X - \mu}{\sigma } > \frac{x - \mu}{\sigma } ) = 0.10$

Where x is the minimum score required to be in the top 10%

Now the $\frac{X - \mu}{\sigma } = Z (The \ Standardized \ value \ of \ X)$

$P(X > x ) = P( Z > \frac{x - \mu}{\sigma } ) = 0.10$

$P(X > x ) = P( Z > \frac{x - 1500}{300} ) = 0.10$

So the critical value of 0.10 from the normal distribution table is $Z_{0.10} = 1.28$

$\frac{x - 1500}{300} = 1.28$

$x = 1884$

6 0

3 years ago