Ask question

Ask question

All categories

3 years ago

14

If 2 - 3i is a solution to the equation x3 - 3x2 + 9x + 13 = 0, what are the other roots of the equation?

1 answer:

OLga [1]3 years ago

4 0

The complex solutions come in pairs and the only difference between them is the sign between the real and imaginary part, so one of the other two solutions is $2+3i$ . The third solution can be easily found using the rational root theorem, and it's equal to -1.

You might be interested in

What is the area of triangle RFG?

vladimir1956 [14]

Answer: you're gonna need to tell us the measurements of the triangle or else we can't help you find the area

7 0

3 years ago

Which expression has the least value?<br> A. 3(33)<br> B. 0 31-33)<br> C. 0-31-33)<br> D. 3(3-3)

Deffense [45]

Answer:

I think it is C but can't be sure because B isn't clear.

Step-by-step explanation:

4 0

3 years ago

Factor this expression completely, then place the factors in the proper location on the grid. (Hint: First, factor using differe

Anna [14]

Answer: x= y =

Step-by-step explanation:

3 0

2 years ago

You roll a standard number cube once. Find P(0)

Sphinxa [80]

??? Im lost in this question, could you be more specific?

7 0

3 years ago

8x^-9+(-3x^-3y-2)(5/x^6y-2)

DaniilM [7]

$8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})$

the first step is to deal with the negative exponents, which causes numbers to go to the other side of the fraction

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

goes to

$\frac{8}{x^9}+(\frac{-3}{x^3y^2})(\frac{5y^2}{x^6})$

now we can simplify the multiplied terms

$\frac{8}{x^9}+(\frac{-15}{x^9})$

Now that we have common bases, we can add the 2 fractions together to get

$\frac{-7}{x^9}$

8 0

3 years ago