If 2 - 3i is a solution to the equation x3 - 3x2 + 9x + 13 = 0, what are the other roots of the equation?

1 answer:

4 0

The complex solutions come in pairs and the only difference between them is the sign between the real and imaginary part, so one of the other two solutions is $2+3i$ . The third solution can be easily found using the rational root theorem, and it's equal to -1.

You might be interested in

Solve (2/3)-(1/x)=5/6

Keith_Richards [23]

$\frac{2}{3} - \frac{1}{x} = \frac{5}{6}$ Multiply both sides by 3
$2 - \frac{1(3)}{x} = \frac{5(3)}{6}$ Simplify the numerators
$2 - \frac{3}{x} = \frac{15}{6}$ Multiply both sides by 6
$12 - \frac{3(6)}{x} = 15$ Simplify the numerator
$12 - \frac{18}{x} = 15$ Multiply both sides by x
12x - 18 = 15x Subtract 12x from both sides
-18 = 3x Divide both sides by 3
-6 = x Switch the sides to make it easier to read
x = -6

Check your answer by plugging -6 in for the x in the original problem:

$\frac{2}{3} - \frac{1}{x} = \frac{5}{6}$ Plug in -6 for x
$\frac{2}{3} - \frac{1}{-6} = \frac{5}{6}$ Change $\frac{2}{3}$ to $\frac{4}{6}$ so all denominators are the same
$\frac{4}{6} - \frac{1}{-6} = \frac{5}{6}$ Change $\frac{1}{-6}$ to $\frac{-1}{6}$ for easier work
$\frac{4}{6} - \frac{-1}{6} = \frac{5}{6}$ Subtract the numerators (4 - (-1) )
$\frac{5}{6}$ = $\frac{5}{6}$

So, x = -6 .

5 0

3 years ago

Solve 1/2(-4x+6)=1/3(9x-24)

irga5000 [103]

x = 11/5 = 2.200 hope this helps

3 0

3 years ago

Read 2 more answers

What is the sum of the arithmetic series: s10 = -20, d = 4, a1 =?

Otrada [13]