Answer:
The zeros are

Step-by-step explanation:
We have been given the equation x^4-6x^2-7x-6=0
Use rational root theorem, we have






Again factor using the rational root test, we get

Using the zero product rule, we have

Therefore, the zeros are

2x -4y= 28
⇒ -4y= 28 -2x
⇒ y= (28 -2x)/ (-4)
⇒ y= 28/(-4) -(2x)/ (-4)
⇒ y= -7 + 1/2x
The final answer is y= -7 + 1/2x~
Subtitute the pair (3,28) to x and y, if the result in right side is -8, then the pair is a solution to the equation
2x - y/2
= 2(3) - 28/2
= 6 - 14
= -8
The result is -8, so the pair (3,28) is a solution
Answer:
A
Step-by-step explanation:
A semester is about 1/2 of the school year which is 4 1/2 or 5 months, its not instant because its 5 months long its not short term commitment because you will have to work with it, and its not a short term goal because 5 months is quite a while in my opinion.
plz give brainliest
Constraints are simply the subjects of an objective function.
The inequality that represents the constraint is: 
Represent the number of hats with x, and the number of scarves with y.
From the question, we have:
- He spends 12 hours to knit a hat
- He spends 6 hours to knit a scarf
So, the equation of the total time spent is:

This time spent is not more than 20 hours.
So, the inequality is

Hence, the inequality that represents the constraint is: 
Read more about constraints at:
brainly.com/question/24574823