Standard formula for arithmetic sequence:
an = a0 + d(n-1)
if we use the two terms given, setting a12 as starting term and a45 as the end term an.
170 = 38 + 33d
170 - 38 = 33d
132 = 33d
132/33 = d
This is the common difference, use it to find the first term.
38 = a0 + (132/33)(12-1)
38 = a0 + (132/33)(11)
38 = a0 + 132/3
38 - 132/3 = a0
38 - 44 = a0
-6 = a0
The starting term is -6
Answer:
No, it's 9
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
hope u find this helpfull
<span>The bacteria in a certain culture double every 7.1 hours.
The culture has 6,500 bacteria at the start. How much after 4 hrs
:
Using the formula: A = Ao*2^(t/d) where
A = amt after t time
Ao = initial amt (t=0)
t = time of action
d = doubling time of the bacteria
;
A = 6500*2^(4/7.1)
A = 6500 * 1.4777
A = 9605 bacteria after 4 hrs</span>
Answer:
5/2 kg
Step-by-step explanation:
The ratio here is 2:6. 2 plus 6 is 8.
Then (2/8) times 10 kg represents the amount of compost needed; that comes to 20/8 kg, or 10/4 kg, or 5/2 kg.
