Selling price of 1st buffalo +Selling price of 2nd buffalo=20000
profit for 1st buffalo=0.05 of cost price of 1st buffalo
loss for 2nd buffalo=0.1 of cost price of 2nd buffalo
1.05(cost price of 1st buffalo)+(0.9)cost price of 2nd buffalo=20000
the buffalo must cost must be same = x (say)
1.05x+0.9x=20000
1.95x=20000
x=10256.41
2x=20512.82
profit=20512.82-20000=512.82
profit %=2.56410 %
Answer:
100
Step-by-step explanation:
6 seconds to select + 14 seconds to complete check out
to complete transaction order of 5 products equal 100 second
Answer:
x = 4
Step-by-step explanation:
Solve for x:
x - 12 + 18 = 10
Hint: | Group like terms in x - 12 + 18.
Grouping like terms, x - 12 + 18 = x + (18 - 12):
x + (18 - 12) = 10
Hint: | Evaluate 18 - 12.
18 - 12 = 6:
x + 6 = 10
Hint: | Isolate terms with x to the left hand side.
Subtract 6 from both sides:
x + (6 - 6) = 10 - 6
Hint: | Look for the difference of two identical terms.
6 - 6 = 0:
x = 10 - 6
Hint: | Evaluate 10 - 6.
10 - 6 = 4:
Answer: x = 4
He increased his prices by 20%.
20% of 25 is 5.
5 + 25 is 30.
Answer:
I just answered it on your other question but
4. AB+BC=AC
6. AC=BD
Step-by-step explanation:
