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mihalych1998 [28]
3 years ago
10

A photographer sells large photos for $27 profit and small photos for an $11 profit.This past year,she sold 126 photos and made

a profit of $2,250.How many of each size photo did she sell?
Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

She sold 72 small photos and 54 large photos.

Step-by-step explanation:

We can set a equations system with the given information. Let X be the quantity of small photos and Z large photos.

We are told that she sold 126 photos in total, so:

X + Z = 126

Also, she earned 2,250 by selling certain quantities of small photo and large photos, so:

$2,250 = $11X + $27Z

From the first equation we get that X=126-Z, replace that into the 2nd equation:

2,250 = 11(126-Z) +27Z

2,250 = 1,386 - 11Z + 27Z

2,250 - 1,386 = 16Z

864 = 16Z

Z = 864/16

Z = 54 is the number of large photos sold. Now find X.

X = 126 - Z

X = 126 - 54

X = 72 is the number of small photos sold.

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What is the measure of angle TSU?
Irina-Kira [14]

Answer:

m<TSU = 65

Step-by-step explanation:

As one can see, the measure of angle (RST) is (90) degrees. This is indicated by the box around the angle. As a general rule, when there is a box around an angle, the angle measure if (90) degrees. It is also given that the measure of angle (RSU) is (25) degrees. As per the given diagram, the sum of the measures of angles (RSU) and (UST) is (RST). Therefore, one can form an equation and solve for the measure of angle (UST).

(RSU) + (UST) + (RST)

Substitute,

25 + (UST) = 90

Inverse operations,

25 + (UST) = 90

UST = 65

(<UST) is another way of naming angle (TSU).

5 0
3 years ago
Read 2 more answers
1. 400 +4<br> 2. 320+ 4<br> 3. 360 +9<br> 4. 5,0005<br> 5. 3,000 +5
Liono4ka [1.6K]

Answer:

1. 400 ÷ 4 = 100

2. 320 ÷ 4 = 80

3. 360 ÷ 9 = 40

4. 5000 ÷ 5 = 1000

5. 3000 ÷ 5 = 600

6 0
3 years ago
Read 2 more answers
Determine whether the given vectors are orthogonal, parallel, or neither. (a) a = 9, 6 , b = −4, 6 orthogonal parallel neither (
labwork [276]

Answer:

(a) Orthogonal, (b) Neither, (c) Parallel, d( Orthogonal

Step-by-step explanation:

a and b are parallel is a=kb

a and b if a dot b = 0

(a) a dot b = (9)(-4)+6(6)=-36+36=0

  a and b are orthogonal

(b) a dot b = 40-7-21=12

    a=kb -> there is no k value satisfying the equation

    a and b are neither parallel or orthogonal

(c) a dot b = -12-108-48=-168

    a=kb  -> k=-3/4 satisfies the equation

    a and b are parallel

(d) a dot b= 9-3-6=0

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3 years ago
3. If ‘A’ can finish a work in ‘n’ days then part of work finished in 1 day is: (a) 1 – n
zaharov [31]

Answer:

If ‘A’ can finish a work in ‘n’ days then part of work finished in 1 day

will be \frac{1}{n}.

Step-by-step explanation:

From the question, it is clear that

  • If ‘A’ can finish a work in ‘n’ days, then
  • we have to determine the part of work finished in 1 day.

So

let 'n' be the number of days A takes to complete the whole work

Let the whole job be denoted as '1'

Thus, the part of work finished in 1 day will be:

                      \:\frac{Total\:work}{Time\:taken\:by\:A\:to\:complete\:the\:work}\:=\frac{1}{n}

Therefore, If ‘A’ can finish a work in ‘n’ days then part of work finished in 1 day will be \frac{1}{n}.

                             

Keywords: work, word problem

Learn more about word problem form brainly.com/question/12419898

#learnwithBrainly

3 0
3 years ago
Write the fractions as fractions with a common denominator 3/4 and 1/3
JulijaS [17]

3/4 and 1/3

4x3 = 12 that will be the common denominator.

For 3/4 we first divide 12/4 = 3 and then multiply 3 x3 = 9 that's the numerator

For 1/3 we first divide 12/3 = 4 and then multiply 1x4 = 4 that's the numerator

The fractions will be rewrited as: 9/12 and 4/12

3 0
1 year ago
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