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mihalych1998 [28]
4 years ago
10

A photographer sells large photos for $27 profit and small photos for an $11 profit.This past year,she sold 126 photos and made

a profit of $2,250.How many of each size photo did she sell?
Mathematics
1 answer:
elena-s [515]4 years ago
3 0

Answer:

She sold 72 small photos and 54 large photos.

Step-by-step explanation:

We can set a equations system with the given information. Let X be the quantity of small photos and Z large photos.

We are told that she sold 126 photos in total, so:

X + Z = 126

Also, she earned 2,250 by selling certain quantities of small photo and large photos, so:

$2,250 = $11X + $27Z

From the first equation we get that X=126-Z, replace that into the 2nd equation:

2,250 = 11(126-Z) +27Z

2,250 = 1,386 - 11Z + 27Z

2,250 - 1,386 = 16Z

864 = 16Z

Z = 864/16

Z = 54 is the number of large photos sold. Now find X.

X = 126 - Z

X = 126 - 54

X = 72 is the number of small photos sold.

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Answer:

(3, 11)

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To check the ordered pair from given option .

lets plug in the value of x from the choices given .

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If we put value of X=5 in equation y = 3x + 2,

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A) (2, 4)

If we put value of X=3 in equation y = 3x + 2,

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Thus, only A) (3, 11) is generated from the equation y = 3x + 2

3 0
3 years ago
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the area of a trapezoid is

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