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mihalych1998 [28]
3 years ago
10

A photographer sells large photos for $27 profit and small photos for an $11 profit.This past year,she sold 126 photos and made

a profit of $2,250.How many of each size photo did she sell?
Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

She sold 72 small photos and 54 large photos.

Step-by-step explanation:

We can set a equations system with the given information. Let X be the quantity of small photos and Z large photos.

We are told that she sold 126 photos in total, so:

X + Z = 126

Also, she earned 2,250 by selling certain quantities of small photo and large photos, so:

$2,250 = $11X + $27Z

From the first equation we get that X=126-Z, replace that into the 2nd equation:

2,250 = 11(126-Z) +27Z

2,250 = 1,386 - 11Z + 27Z

2,250 - 1,386 = 16Z

864 = 16Z

Z = 864/16

Z = 54 is the number of large photos sold. Now find X.

X = 126 - Z

X = 126 - 54

X = 72 is the number of small photos sold.

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Veronica has been saving dimes and quarters she has 110 coins in all and the total value is 18.50 how many dimes and quarters do
Lady_Fox [76]

This problem can be solved by the chicken rabbits method or you can just do simple algebra.

I.) Chicken and rabbits method

First assume all 110 coins are dimes and none are quarters.

We will have a total value of 11 dollars

Now for each dime we switch out for a quarter, we adds 15 cents to the total value.

18.50-11=7.50 dollars

There are 750/15=50 group of 15 cents in the 7 dollars and 50 cents.

This also meant that we need to switch out 50 dimes for 50 quarters.

So we have 50 quarters.

That first method is very good and very quick once you get the hang of it, now I'm going to show you the algebraic way to solve this.

Let's say there are x dimes and y quarters.

Set up equation

x+y=110

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Now solve multiply first equation by 10

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subtract

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Now we set the numbers of quarters to y so the answer is 50 quarters.

I personally recommend using algebra whenever you can because the practice is very important and you will eventually get really fast at setting up and solving equations. The first method is faster in this case but the second is more generalize, hope it helps.

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