Dividing a Fraction into Equal Groups
1 answer:
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Answer: 14 members take physics but not mathematics
Step-by-step explanation:
Please see the attached for a diagrammatic representation of this situation.
Since there are 40 members but 8 did not offer any of mathematics or physics, then:-
40 - 8 = 32
So, 32 members of the fraternity offer maths, physics or both.
5 members offer both mathematics and physics .
Since 5 members offer both mathematics and physics, the number of members that offer maths alone = 18 - 5
Let us use "P" to represent the number of members that offer physics. Therefore, the number of members that offer only physics = (P - 5)
Now, if we add up the members that offered maths only, the members that offered both mathematics and physics and the members that offered only physics, it will be equal to the 32 members that offered at least a subject.
Therefore, (18 - 5) + 5 + (P - 5) = 32
18 - 5 + 5 + P - 5 = 32
18 + P - 5 = 32
P + 13 = 32
P = 32 - 13
P = 19
19 members offered physics out of the 32 members that offered maths, physics or both.
To find out the number of people or members that offered physics only, we subtract the number of members that offered the two subjects (5) from a total of 19 members that offered Physics
19 - 5 = 14
Therefore, 14 members of the fraternity offer only physics
Answer:
C) 40
Step-by-step explanation:
For every one day your work is 5 hours.
1 day = 5 hours
Set up a proportion so it would be:
4 days x 5 hours = 20 hours/week
So now you know you know you work 20 hours/week, then multiply by 2 since they're asking how many hours will you work in two weeks:
20 hours x 2 weeks = 40 hours in two weeks