Answer: 0.31 or 31%
Let A be the event that the disease is present in a particular person
Let B be the event that a person tests positive for the disease
The problem asks to find P(A|B), where
P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))
In other words, the problem asks for the probability that a positive test result will be a true positive.
P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)
P(A) = 0.009 (probability the disease is present in any particular person)
P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)
P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)
P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)
= 0.00882 / 0.02864 = 0.30796
*round however you need to but i am leaving it at 0.31 or 31%*
If you found this helpful please mark brainliest
Hi, what exactly is the question ?
Answer:
x-7-5/x+4
So answer C
Step-by-step explanation:
Net yardage=3-6-4+5=-2
So the team lost 2 yards in four plays...
You can write this as a ratio to find the answer, but you first need to convert the gallon of white paint into ounces, which is 160 ounces. The ratio, red to blue to white, is 4:28:160, which you can simplify by dividing by 4 into 1:7:40. If 80 ounces of red tint are used, you need to multiply each value in the ratio by 80, which gives you 80:560:3200. This shows that you need 560 ounces of blue tint, which can also be written as 3.5 gallons. I hope this helps!
