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goldfiish [28.3K]
3 years ago
12

15, 19, 23, 27.... what is the 52nd term in the arithmetic sequence?​

Mathematics
1 answer:
Solnce55 [7]3 years ago
4 0

Answer:

219

Step-by-step explanation:

a is the number needed to add from the first to the second which is 4(must be constant)

b is the term zero means 15-a which is 15-4=11

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Miranda’s financial aid stipulates that her tuition not exceed $1200. If her college charges a $90 registration fee for the term
Arlecino [84]

Answer: the greatest number of courses for which miranda can register is 2

Step-by-step explanation:

Let x represent the number of courses for which Miranda can register.

If her college charges a $90 registration fee for the term plus $475 per course, it means that the total amount that the college charges for x courses would be

475x + 90

Miranda’s financial aid stipulates that her tuition not exceed $1200(it must be at most $1200). This means that

475x + 90 ≤ 1200

475x ≤ 1200 - 90

475x ≤ 1110

x ≤ 1110/475

x ≤ 2.34

3 0
4 years ago
Which integral gives the area of the region in the first quadrant bounded by the graphs of y^2 = x − 1, x = 0, y = 0, and y = 2?
r-ruslan [8.4K]
Weird that the only choices are given as integrals with respect to x. (Integration along the y axis would be way easier, but whatever)

The fourth option should do it.
5 0
3 years ago
Can you help me with this.
user100 [1]

I hope this helps you

7 0
4 years ago
What is the area of the figure below? <br> Haaaaalp please
Thepotemich [5.8K]
A_1=6\cdot5=30\ [in^2]\\\\A_2= \frac{1}{2} \cdot[15+(7+5)]\cdot4=2\cdot(15+12)=2\cdot27=54\ [in^2]\\\\A=A_1+A_2=30+54=84\ [in^2]

4 0
4 years ago
Read 2 more answers
Evaluate 1/4 c + 3d when c = 6 and d = 7
Naddika [18.5K]

           \rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}

       <em>Evaluate 1/4c+3d when c=6, and d=7.</em>

<em />

<em>         </em>\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

       Replace c with 6, and d with 7:-

     \Large\text{$\displaystyle\frac{1}{4} (6)+3(7)$}

\bigstar On simplification,

   \Large\text{$\displaystyle\frac{1}{4} \times\frac{6}{1}+21$}

\bigstar On further simplification,

    \Large\text{$\displaystyle\frac{6}{4} +21$}

\bigstar On further simplification,

     \Large\text{$\displaystyle\frac{6}{4}+\frac{84}{4}$}

\bigstar Adding the numerators,

\Large\text{$\displaystyle\frac{90}{4}$}

\bigstar Finally, Reducing the fraction:-

\Large\text{$\displaystyle\frac{45}{2}$}

\Uparrow \mathbb{OUR\:SIMPLIFIED\:EXPRESSION}

<h3>Good luck with your studies.</h3>

         \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}

8 0
2 years ago
Read 2 more answers
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