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Karo-lina-s [1.5K]
3 years ago
13

Three of the vertices of a rectangle have coordinates (-1, -1), (6, -1), and (-1, 2). What are the coordinates of thefourth vert

ex?
Mathematics
1 answer:
Ivenika [448]3 years ago
6 0

Answer:

(6,2)

Step-by-step explanation:

Diagonals have the same midpoint

(6-1)/2, (-1+2)/2 = (-1+x)/2, (-1+y)/2

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Please help! this is hard for me!
weqwewe [10]

Answer:

$12.31

Step-by-step explanation:

Think of the original rate of pay as being 100%.

If your rate is increasing by 7%, it will now be 107% of the original rate (since 100% + 7% = 107%)

To find 107% of $11.50, convert 107% into a decimal

⇒ 107% = 107/100 = 1.07

then multiply this by the original rate to get the new increased rate:

⇒ $11.50 × 1.07 = $12.305

Rounding this to the nearest hundred = $12.31

Alternatively, you can find 7% of $11.50 and then add this to $11.50.

⇒ 7% = 7/100 = 0.07

Therefore, 7% of $11.50 = 0.07 × $11.50 = $0.805

Add this to the original rate:

$11.50 + $0.805 = $12.305

Rounding this to the nearest hundred = $12.31

8 0
2 years ago
What is the value of x in the equation 6 = -3(x + 2)?
Sphinxa [80]

Answer:

x=-4

Step-by-step explanation:

Dividing both sides by -3, you get x+2=-2. So x=-4.

4 0
3 years ago
Read 2 more answers
The depth of a swimming pool is 8.5 meters. what is half of the depth in millimeters
nydimaria [60]
Half of 8.5 is 4.25

4.25*100=4250
5 0
3 years ago
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Find the f^-1(x) and it’s domain
borishaifa [10]

Answer:

f^{-1}(x) = (x + 8)^2

x \ge -8

Step-by-step explanation:

Given

f(x) = \sqrt x - 8

Solving (a): f^{-1}(x)

We have:

f(x) = \sqrt x - 8

Express f(x) as y

y = \sqrt x - 8

Swap x and y

x = \sqrt y - 8

Add 8 to both\ sides

x + 8 = \sqrt y - 8 + 8

x + 8 = \sqrt y

Square both sides

(x + 8)^2 = y

Rewrite as:

y = (x + 8)^2

Express y as: f^{-1}(x)

f^{-1}(x) = (x + 8)^2

To determine the domain, we have:

The original function is f(x) = \sqrt x - 8

The range of this is: f(x) \ge -8

The domain of the inverse function is the range of the original function.

<em>Hence, the domain is:</em>

x \ge -8

3 0
3 years ago
Which type of transformation could cause a change in the period of a tangent or cotangent function? vertical shift phase shift v
siniylev [52]
The horizontal stretch is the correct answer. A period is the distance on the x-axis that it takes for the tangent or cotangent function to repeat itself. Stretching it out horizontally will lengthen that distance and therefore change the period.
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3 years ago
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