What is x+5 over x = 5 over 4

KiRa [710]

<h2>Answer:</h2><h2>52.7856 cm</h2>

Solution,

diameter=16.8 cm

radius=8.4 cm

Circumference of circle=2 pi r

 = 2*3.142*8.4

 =52.7856 cm

Hope it helps

Good luck on your assignment

5 0

3 years ago

This week laptops are 25% off. If a laptop costs $340, what is its sale price?

Juli2301 [7.4K]

Answer:

$25

Step-by-step explanation:

i have an odd method of solving these types of equations

25x=100

x=4

340/4 = 85

85 x 3 = 255

5 0

3 years ago

Read 2 more answers

A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

3 years ago

The graph shows how the length of a buildings shadow at a certain time of day is related to the height of the building.

Artyom0805 [142]

A. the graph represents a relation because it contains ordered pairs (x,y). It is also a function because there are no repeating x values.

B. (0,0) (8,6)
slope = (6 - 0 ) / (8 - 0) = 6/8 = 3/4
so ur equation is : y = 3/4x or f(x) = 3/4x <===

C. the variable x represents the height of the building and the variable y (or f(x)) represents the total length of the shadow

3 0

3 years ago

Read 2 more answers

How do you change 24 2\5 into decimal?

seropon [69]

24 and 2/5=24+2/5
24=24

0.1=1/10
2/5=x/10
times both sides by 10
20/5=x
4=x
2/5=4/10=0.4

24 and 2/5=24+0.4=24.4

5 0

3 years ago

Read 2 more answers