Question

What quantity of 75 per cent acid solution must be mixed with a 30 per cent solution to produce 1080 mL of a 50 per cent solution?

Answer 1

Answer: 480 mL, 600 mL

Step-by-step explanation:

Given

The concentration of the first acid is 75%

The concentration of the second acid is 30%

The final mixture has a concentration of 50%

The final volume is 1080 mL

Suppose x and y be the volume of the first and second acid

$\therefore x+y=1080\quad \ldots(i)\\0.75x+0.3y=0.5\times 1080\quad \ldots(ii)$

Solving the above equations we get

$x=480,y=600$

So, the quantity of the first acid is 480 mL and 600 mL for the second mixture.